Question

我正在对c编程进行分配，例如，如果用户输入，则对两个二进制数进行（+，-，*，/）操作：“ 1001 + 1010” 必须添加两个二进制文件并给出输出“ 010011”

我的代码只能逐步获取每个输入（获取第一个二进制文件然后获取第二个二进制文件，然后选择运算符（+，-，*，/）然后生成答案），然后生成答案，但是赋值却认为要取整立即（1001 + 1010并给出答案010011）

#include <stdio.h>

int main()

{

    int num, num2, binary_val, binary_val2, decimal_val = 0, decimal_val2 = 0, base = 1, rem, base2 = 1, rem2, sum;
    char oprtr;

    printf("Enter the first binary number(1s and 0s) \n");

    scanf("%d", &num);

    binary_val = num;
    printf("Enter the second binary number(1s and 0s) \n");

    scanf("%d", &num2);
    binary_val2 = num2;

    printf("choose operation +,-,/,* \n");

    scanf("%char", &oprtr);

    while (num > 0)

    {

        rem = num % 10;

        decimal_val = decimal_val + rem * base;

        num = num / 10;

        base = base * 2;
    }
    while (num2 > 0)

    {

        rem2 = num2 % 10;

        decimal_val2 = decimal_val2 + rem2 * base2;

        num2 = num2 / 10;

        base2 = base2 * 2;
    }

    if (oprtr == '+')
    {
        sum = decimal_val + decimal_val2;
    }
    else if (oprtr == '*' || oprtr == 'x' || oprtr == 'X')
    {
        sum = decimal_val * decimal_val2;
    }
    else if (oprtr == '-')
    {
        sum = decimal_val * decimal_val2;
    }
    else if (oprtr == '/')
    {
        sum = decimal_val / (float)decimal_val2;
    }
    else
    {
        printf("error");
    }

    int decimal_num, remainder, binary = 0;

    while (sum > 0)

    {

        remainder = num % 2;

        /*  To count no.of 1s */

        if (remainder == 1)

            binary = binary + remainder * base;

        sum = sum / 2;

        base = base * 10;
    }

    printf("The Binary number of the first one is = %d \n", binary_val);
    printf("The Binary number of the second one is  = %d \n", binary_val2);

    printf("Its decimal equivalent is = %d \n", decimal_val);
    printf("Its decimal equivalent is = %d \n", decimal_val2);

    printf("And their Value is = %d \n", sum);
}

Answer 1

在读取运算符之前，您必须绕过第二个数字之后输入的\ n，例如getchar(); oprtr = getchar();而不是您的scanf

您将始终打印值为0，因为您打印的是总和而不是二进制

您错过了在最后一刻之前将基数重置为1的情况

其他说明

要将两次用同一代码编写的数字从二进制转换为十进制，最好添加专用功能
要求在一行中输入num1 {opr} num2更简单，因为在执行一次唯一的scanf之后，您只需执行一次：scanf("%d%c%d", &num, &oprtr, &num2);

如何从用户那里获取两个二进制数和运算并给出答案

1 个答案: