在index.php上有链接编辑,当我按edit时,应将其重定向到edit.php并根据我按edit的行自动填写表格,但不会根据表格进行填写
index.php
<?php
$tampil="SELECT * FROM obat";
$result=mysqli_query($conn,$tampil);
if(mysqli_num_rows($result)){
while ($row=mysqli_fetch_assoc($result)) {
?>
<tr>
<td><?=$row['id_obat']?></td>
<td><?=$row['namaObat']?></td>
<td><?=$row['jenisObat']?></td>
<td><?=$row['stok']?></td>
<td><a class="btn btn-success" href="edit.php">Edit</a>
<a class="btn btn-danger" href="">Delete</a>
</td>
</tr>
<?php
}
}
?>
edit.php
<?php
include('config.php');
$id_obat = 'id_obat';
$namaObat = 'namaObat';
$jenisObat = 'jenisObat';
$stok = 'stok';
if (isset($_GET['id_obat'])) {
$sql="SELECT * FROM obat WHERE id_obat=$id_obat";
$result=mysqli_query($conn,$sql);
$row=mysqli_fetch_assoc($result);
}
?>
<form method="POST" action="edit.php">
<div>
<label>Nama Obat</label>
<input type="text" class="form-control" name="namaObat" value="<?=$namaObat?>">
</form>
答案 0 :(得分:0)
href="edit.php"
之后没有get参数。即href="edit.php?id_obat=<?php echo $row['id_obat'];?>"
在编辑页面中,您没有将GET参数分配给$id_obat
,而只是分配了字符串id_obat。
您应该首先查看SQL Injection并转义任何GET参数,甚至最好使用Prepared Statements。
请以以下示例为例,并查看我发布的两个保护数据库的链接。更改是...检查GET参数,然后将其分配给变量。
include('config.php');
$namaObat = 'namaObat';
$jenisObat = 'jenisObat';
$stok = 'stok';
if (isset($_GET['id_obat'])) {
$id_obat = mysql_real_escape_string($_GET['id_obat']);
$sql="SELECT * FROM obat WHERE id_obat=$id_obat";
$result=mysqli_query($conn,$sql);
$row=mysqli_fetch_assoc($result);
}
?>
<form method="POST" action="edit.php">
<div>
<label>Nama Obat</label>
<input type="text" class="form-control" name="namaObat" value="<?=$namaObat?>">
</form>