Question

我正在为我的OCR GCSE编程项目进行音乐测验。 python程序的目的是从数组中生成随机选择的歌曲，显示歌曲的首字母并显示艺术家，然后允许用户猜测歌曲的名称。歌曲数组和艺术家数组存储在单独的外部记事本文件中，并正确加载，显示歌曲和艺术家的缩写。我的问题是，即使用户正确猜出了歌曲名称，程序也会显示它不正确，并且与用户输入的歌曲名称不匹配。

我尝试显示歌曲名称以确保正确猜出歌曲名称，并且还尝试复制歌曲名称并将其复制到用户输入中

import random
songlistfilecontents = open("songlist.txt", "r")
songlist = songlistfilecontents.readlines()
artistlistfilecontents = open("artistlist.txt", "r")
artistlist = artistlistfilecontents.readlines()
randomnumber = random.randint(0,11)
randomsong = songlist[randomnumber]
randomartist = artistlist [randomnumber]
initialsofsong = "".join(item[0].upper() for item in randomsong.split())

counter = 0
print("The songs' initials are " ,initialsofsong, " and the name of the 
artist is " ,randomartist)
print (randomsong)
songnameguess = input("Guess the name of the song!")
counter = counter + 1
while songnameguess != randomsong:
    songnameguess = input("Nope! Try again!")
    counter = counter + 1
if counter >=3 and songnameguess != randomsong:
    print ("Sorry, you've had two chances. Come back soon!")
elif songnameguess == randomsong:
    print ("Well done!")

我希望程序显示“做得好！”如果用户对歌曲的猜错不超过3次并正确猜对了答案。但是，程序从不显示此内容，而是显示Nope！再试一次并提示输入Songnameguess，直到用户猜测了3次（错误或正确），然后打印对不起，您有两次机会。很快回来！

Answer 1

就像@Barmar在阅读文本文件时在注释中说的那样，您必须考虑以下事实：您将在每一行的末尾获得换行符。但是您的代码中还有另一个错误：在您的while循环中，您永远不会检查用户给出的答案是否超过您想要授予的答案。因此，用户将一直停留在该循环中，直到他给出正确的答案为止。

因此，只需进行很少的修改，它就会像：

解决方案1 

import random
songlistfilecontents = open("songlist.txt", "r")
songlist = songlistfilecontents.readlines()
artistlistfilecontents = open("artistlist.txt", "r")
artistlist = artistlistfilecontents.readlines()
randomnumber = random.randint(0,11)
randomsong = songlist[randomnumber]
randomsong = randomsong.rstrip("\n")
randomartist = artistlist [randomnumber]
initialsofsong = "".join(item[0].upper() for item in randomsong.split())

counter = 0
print("The songs' initials are " ,initialsofsong, " and the name of the artist is " ,randomartist)
print (randomsong)
songnameguess = input("Guess the name of the song!")
counter = counter + 1
while counter < 3 and songnameguess != randomsong :
    songnameguess = input("Nope! Try again!")
    counter = counter + 1

if counter >=3 and songnameguess != randomsong:
    print ("Sorry, you've had two chances. Come back soon!")
elif songnameguess == randomsong:
    print ("Well done!")

Answer 2

但是我们可以走得更远。

解决方案2

import random

with open("songlist.txt", "r") as songlistfilecontents:
    songlist = songlistfilecontents.readlines()

with open("artistlist.txt", "r") as artistlistfilecontents:
    artistlist = artistlistfilecontents.readlines()

randomnumber = random.randint(0,11)
randomsong = songlist[randomnumber]
randomsong = randomsong.rstrip("\n")
randomartist = artistlist [randomnumber]
initialsofsong = "".join(item[0].upper() for item in randomsong.split())


print("The songs' initials are", initialsofsong, "and the name of the artist is", randomartist)
print (randomsong)
# First try
songnameguess = input("Guess the name of the song! ")
nb_tries_left = 2
answer_not_found = (songnameguess != randomsong)
while nb_tries_left > 0 and answer_not_found:
    songnameguess = input("Nope! Try again! ")
    nb_tries_left -= 1
    answer_not_found = (songnameguess != randomsong)

if answer_not_found:
    print ("Sorry, you've had two chances. Come back soon!")
else:
    print ("Well done!")

我已经用context managers打开和读取文件了
我使用nb_tries_left来记录停止之前剩余的尝试次数。我没有将值累加起来，而是先将该值设置为零，然后递减为零。

Answer 3

我们可以走得更远：

解决方案3

import random

with open("songlist.txt", "r") as songs_file:
    with open("artistlist.txt", "r") as artists_file:
        songs_and_artists = [(song.rstrip('\n'), artist.rstrip('\n'))
                             for (song, artist) in zip(songs_file, artists_file)]

random_song, random_artist = random.choice(songs_and_artists)
songs_intials = "".join(item[0].upper() for item in random_song.split())


print("The songs' initials are", songs_intials, "and the name of the artist is", random_artist)
print(random_song)

nb_tries_left = 3
guess = input("Guess the name of the song! ")
nb_tries_left -= 1

finished = False
while not finished:
    answer_found = (guess == random_song)
    if not answer_found:
        guess = input("Nope! Try again! ")
        nb_tries_left -= 1

    finished = (answer_found or nb_tries_left <= 0) 

if answer_found:
    print ("Well done!")
else:
    print ("Sorry, you've had two chances. Come back soon!")

我使用文件对象可迭代的事实。因此，使用zip()，我创建了一个包含歌曲和艺术家组合的元组列表。
我使用random.choice()随机选择一首歌曲和一位歌手

您如何对照python中的用户输入检查从数组随机生成的值？

3 个答案: