Question

当我尝试在其他标签之间插入标签时，遇到JTabbedPane的奇怪问题。 UI呈现了预期的样子，但是getComponentAt()返回了错误的组件。

在我的应用程序中，用户应该可以按自己想要的任何顺序重新排列标签。为此，我使用insertTab()方法插入标签。这样做时，标签会消失，其余标签的内容有误。

import java.awt.Component;

import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JTabbedPane;

public class InsertTabExample extends JFrame {

    public InsertTabExample() {
        final JTabbedPane pane = new JTabbedPane();

        addTabsInReverseOrder(pane);
        dumpTabs(pane);

        add(pane);

        this.setSize(640, 480);
        this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        this.setVisible(true);
    }

    private void addTabsInReverseOrder(final JTabbedPane pane) {
        for(int i = 0; i < 10; i++) {
            final String tabLabel = String.format("tab #%d", i);
            final String componentLabel = String.format("component #%d", i);

            final JLabel component = new JLabel(componentLabel);
            component.setName(componentLabel);

            pane.insertTab(tabLabel, null, component, null, 0);
        }
    }

    private void dumpTabs(final JTabbedPane pane) {

        for(int i = 0; i < pane.getTabCount(); i++) {
            final String tabName = pane.getTitleAt(i);
            final Component component = pane.getComponent(i);

            final int componentIndex = pane.indexOfComponent(component);

            System.out.println(String.format("Index %d -> tab '%s' -> component '%s' -> component index %d", i, tabName, component.getName(), componentIndex));
        }
    }

    public static void main(String[] args) {
        new InsertTabExample();
    }
}

如预期的那样，用户界面以相反的顺序显示选项卡（从“选项卡＃9”开始），并且还向每个选项卡显示正确的组件。

控制台上的输出显示不同的内容。我希望得到


    Index 0 -> tab 'tab #9' -> component 'component #9' -> component index 9
    Index 1 -> tab 'tab #8' -> component 'component #8' -> component index 8
    Index 2 -> tab 'tab #7' -> component 'component #7' -> component index 7
    Index 3 -> tab 'tab #6' -> component 'component #6' -> component index 6
    Index 4 -> tab 'tab #5' -> component 'component #5' -> component index 5
    Index 5 -> tab 'tab #4' -> component 'component #4' -> component index 4
    Index 6 -> tab 'tab #3' -> component 'component #3' -> component index 3
    Index 7 -> tab 'tab #2' -> component 'component #2' -> component index 2
    Index 8 -> tab 'tab #1' -> component 'component #1' -> component index 1
    Index 9 -> tab 'tab #0' -> component 'component #0' -> component index 0

但是我得到的是


    Index 0 -> tab 'tab #9' -> component 'component #0' -> component index 9
    Index 1 -> tab 'tab #8' -> component 'component #1' -> component index 8
    Index 2 -> tab 'tab #7' -> component 'component #2' -> component index 7
    Index 3 -> tab 'tab #6' -> component 'component #3' -> component index 6
    Index 4 -> tab 'tab #5' -> component 'component #4' -> component index 5
    Index 5 -> tab 'tab #4' -> component 'component #5' -> component index 4
    Index 6 -> tab 'tab #3' -> component 'component #6' -> component index 3
    Index 7 -> tab 'tab #2' -> component 'component #7' -> component index 2
    Index 8 -> tab 'tab #1' -> component 'component #8' -> component index 1
    Index 9 -> tab 'tab #0' -> component 'component #9' -> component index 0

按预期顺序返回选项卡标签，但按相反顺序列出组件。

这是怎么回事？如何正确获取特定选项卡的组件？

感谢任何提示！

Answer 1

TabbedPane保持索引从0到getTabCount()的顺序-因此最后一个标签不能为0-因此，当您添加标签时，请放置正确的索引：{{1 }}

getTabCount()-i

另一个错误-private void addTabsInReverseOrder(final JTabbedPane pane) { for(int i = 0; i < 10; i++) { final String tabLabel = String.format("tab #%d", i); final String componentLabel = String.format("component #%d", i); final JLabel component = new JLabel(componentLabel); component.setName(componentLabel); pane.insertTab(tabLabel, null, component, null, pane.getTabCount()-i); } } private void dumpTabs(final JTabbedPane pane) { for(int i = 0; i < pane.getTabCount(); i++) { final String tabName = pane.getTitleAt(i); final Component component = pane.getComponentAt(i); final int componentIndex = pane.indexOfComponent(component); System.out.println(String.format("Index %d -> tab '%s' -> component '%s' -> component index %d", i, tabName, component.getName(), componentIndex)); } }获取此容器中的第n个组件。并且您需要替换为pane.getComponent(i)，它会返回特定索引处的组件。

输出将是：

pane.getComponentAt(i)

因此选项卡和组件的索引将不会相反-它的索引从0到Index 0 -> tab 'tab #9' -> component 'component #9' -> component index 0 Index 1 -> tab 'tab #8' -> component 'component #8' -> component index 1 Index 2 -> tab 'tab #7' -> component 'component #7' -> component index 2 Index 3 -> tab 'tab #6' -> component 'component #6' -> component index 3 Index 4 -> tab 'tab #5' -> component 'component #5' -> component index 4 Index 5 -> tab 'tab #4' -> component 'component #4' -> component index 5 Index 6 -> tab 'tab #3' -> component 'component #3' -> component index 6 Index 7 -> tab 'tab #2' -> component 'component #2' -> component index 7 Index 8 -> tab 'tab #1' -> component 'component #1' -> component index 8 Index 9 -> tab 'tab #0' -> component 'component #0' -> component index 9。

当使用insertTab（）插入制表符时，JTabbedPane.getComponentAt（）似乎返回错误的组件

1 个答案: