Question

我很难弄清楚如何使用rspec和shoulda_matchers测试强大的参数。

无论我尝试了什么，我总是收到以下消息：RSpec::Expectations::ExpectationNotMetError: Expected POST #create to restrict parameters on :language_name to :name, but it did not restrict any parameters.

这是我的控制者：

class LanguageNamesController < CrudController
  inherit_resources
  actions :all, :except => [:show]

  private
    def language_name_params
      params.require(:language_name).permit(:name)
    end
end

这是测试：

require 'rails_helper'
RSpec.describe LanguageNamesController, type: :controller do
  describe "parameters" do
    it do
     lm_params = {
       language_name: {
         name: 'John'
       }
     }
     expect(subject).to permit(:name).for(:create, params: { params: lm_params }).on(:language_name)
    end
  end
end

此外，我已经尝试过并得到相同的结果：

it do
  subject.params = ActionController::Parameters.new(language_name: {foo: 'bar', name: 'baz'})
  expect(subject).to permit(:name).for(:create).on(:language_name)
end

如果我这样尝试，我会得到ArgumentError: unknown keyword: language_name：

it do
 lm_params = {
   language_name: {
     name: 'John'
   }
 }
 expect(subject).to permit(:name).for(:create, params: lm_params).on(:language_name)
end

我正在使用：

红宝石2.5.1
导轨5.1.6
shoulda-matchers 3.1.2

有人知道如何解决这个问题吗？

谢谢！

这是我的测试方法：

it do
  faker_name = Faker::Name.name

  params = {
    language_name: {name: faker_name, other_attribute: "other value"},
    extra: {extra: 1}
  }
  get :index, params: params

  expect(subject.send(:language_name_params)).to eq({"name"=> faker_name})
end

Answer 1

您不需要创建lm_params。匹配者应该为您模拟params对象。

如果您只需要测试权限，则可以执行should permit(:name).for(:create)

如果您需要检查允许的参数上的值：should permit(:name).for(:create, params: {name: 'John'})

strong_parameters_matcher.rb

文档中有很好的示例

编辑：另一个好的文档来源是rubydoc for shoulda matchers。

使用shoulda_matchers测试强大的参数

1 个答案: