Question

我创建了以下两个模型...

const Account = sequelize.define("account",
{
    id_account: {
        type: Sequelize.INTEGER.UNSIGNED,
        primaryKey: true,
        autoIncrement: true
    },
    name: {...},
    surname: {...},
    username: {...},
    password: {...}
},
{
    name: {
        singular: "Account",
        plural: "Accounts"
    },
    freezeTableName: true,
    hooks: {
        beforeSave: ((account, options) => {
            return bcrypt.hash(account.password, 10)
                .then(hash => {account.password = hash;})
                .catch(err => {throw new Error();});
        })
    }
});

const Genre = sequelize.define("genre",
{
    genre_name: {
        type: Sequelize.STRING(40),
        primaryKey: true
    },
    url_img: {
        type: Sequelize.STRING(40),
        allowNull: false
    }
},
{
    name: {
        singular: "Genre",
        plural: "Genres"
    },
    freezeTableName: true
});

...以及以下关联

Account.Genres = Account.belongsToMany(Genre, {
    through: "AccountGenre",
    foreignKey: "ref_account"
});
Genre.Accounts = Genere.belongsToMany(Account, {
    through: "AccountGenre",
    foreignKey: "ref_genre"
});

我创建了以下类型：摇滚，金属，流行，铁杆。现在，我想创建一个帐户并将其与3种类型相关联。以下代码创建了Account，但未与AccountGenre表中的现有流派建立关联：

const genresArray = ["Rock", "Metal", "Pop"];
const account = {...} // I have an object with account properties
Account.create({
    name: account.name,
    surname: account.cognome,
    username: account.nome_utente,
    password: account.password,
    genres: genresArray
}, {
    include: [Genre]
});

此代码有什么问题？

Answer 1

这里的问题是您给了复数名称“流派”的关联。您需要在include语句中添加相同的内容。

包括：[类型]

如何创建与现有对象关联的元素

1 个答案: