Question

我确信解决问题的方法很容易被忽略。

我要做的是，当用户输入！add不和谐时，机器人会将它们添加到一个数组中（供6个人拾起游戏）。

当前，当第一个用户键入！add时，它将其添加到数组中。当第二个用户执行！add时，数组不会添加第二个用户，而是将第一个用户保留在数组中。

它的工作方式是用户1和用户2都在数组中。

const pugSize = 6; // Maximum amount of players in the PUG
const pugMembers = []; // Array to hold the members in the PUG

function checkPugSize(){
    if (pugMembers.length == 6){
        //TODO Create the two teams
        console.log(`PUG IS FULL: ${pugMembers.length}`);
    }else{
        console.log(`THE PUG IS NOT FULL: ${pugMembers.length}`);
    }
}

function addUserPug(msg){
    // console.log(msg.author);
    // Add user to the pugMembers Array if the array is not full
    if (pugMembers<=6){
        pugMembers.push(msg.author.username);
    }else{ // Create a new pug and pass the user into the array
        console.log("TODO: Create a new pug when current array is filled");
        // createNewPug(msg.author.username);
    }
    msg.channel.send(`${msg.author} added to queue ${pugMembers.length}/6.`); // Mention the user that they are added into the queue
    // msg.reply(' added to queue. ' + `${pugMembers.length}/6`);
    msg.delete()
    .then(msg => console.log(pugMembers))
    .catch(console.error);
}

client.on('ready', () => {
    console.log(`Logged in as ${client.user.tag}!`);
});

client.on('message', msg => {
    if (msg.content == '!size'){
        msg.channel.send(`Current PUG size: ${pugMembers.length}`);
    }
    if (msg.content === '!add'){
        // console.log(msg.author);
        checkPugSize();
        addUserPug(msg);
    }
});

Answer 1

使用

pugMembers.length <= 6

您当前的陈述在行为方面未定义。

将用户添加到数组

1 个答案: