我已经使用has_many:through关联来处理用户和项目这两个模型之间的多对多关系,但是似乎存在一些错误,因为在多对一关系中运行良好的查询是引发错误。有人可以检查一下!模式文件如下:
ActiveRecord::Schema.define(version: 2018_12_19_170114) do
create_table "project_users", force: :cascade do |t|
t.integer "user_id"
t.integer "project_id"
t.index ["project_id"], name: "index_project_users_on_project_id"
t.index ["user_id"], name: "index_project_users_on_user_id"
end
create_table "projects", force: :cascade do |t|
t.text "content"
t.integer "user_id"
t.datetime "created_at", null: false
t.datetime "updated_at", null: false
t.string "picture"
t.string "title"
t.index ["user_id"], name: "index_projects_on_user_id"
end
create_table "users", force: :cascade do |t|
t.string "name"
t.string "email"
t.integer "enroll"
t.datetime "created_at", null: false
t.datetime "updated_at", null: false
t.string "password_digest"
t.boolean "admin", default: false
t.index ["email"], name: "index_users_on_email", unique: true
end
end
user.rb文件包含以下代码:
类用户 project_user.rb文件具有代码: 该错误由代码引发: 错误是:The project.rb file has the code:
class Project < ApplicationRecord
has_many :project_users
has_many :users, :through => :project_users
class ProjectUser < ApplicationRecord
belongs_to :project, foreign_key: true
belongs_to :user, foreign_key: true
end
class StaticPagesController < ApplicationController
def home
if logged_in?
@project = current_user.projects.build
@feed_items = current_user.feed.paginate(page: params[:page])
end
end
<% if @user.projects.any? %>
<h3>Projects (<%= @user.projects.count() %>)</h3>
SQLite3::SQLException: no such column: project_users.true: SELECT 1 AS one FROM "projects" INNER JOIN "project_users" ON "projects"."id" = "project_users"."true" WHERE "project_users"."user_id" = ? LIMIT ?
答案 0 :(得分:0)
这是一个可怕的措辞问题,正如评论所建议的那样,请包括错误消息,否则无法调试。
一目了然,我可以在您的架构中看到以下问题:
project_users
user_id
t.references :user
助手而不是t.integer :user_id
。然后,您可以传递index: true, foreign_key: true
选项来设置索引和外键。