在这段代码中,我想用(-)
运算符替换逗号和空格。如果keyword
是java developer, hibernate, struts,
,而city
是delhi, noida, mumbai
,我该怎么做?同样,逗号和空格也不会显示在URL中,例如,
。
$("#search").click(function(e) {
e.preventDefault();
str1 = $("#keyword").val();
str2 = str1.replace(", ","-");
keyword = str2.replace(" ", "-");
keys1 = $("#city").val();
keys2 = keys1.replace(", ","-");
city = keys2.replace(" ", "-");
window.location.href = "<?php echo base_url(); ?>" + keyword + "-in-" + city;
});
答案 0 :(得分:2)
用破折号替换所有逗号和空格,然后从字符串中删除最后一个破折号。
$("#search").click(function(e){
var str = $("#keyword").val().replace(/[,\s]+/g, '-').replace(/-$/, '');
console.log(str);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button id="search">search</button>
<input type="text" id="keyword" value="java developer, hibernate, struts, ">
答案 1 :(得分:1)
检查
$("#search").click(function(e) {
e.preventDefault();
keyword = $("#keyword").val();
if(keyword.length>0){
keyword = keyword.subString(0,(keyword.length-1));
keyword = keyword.replace(/, /g, "-");
keyword = keyword.replace(/ /g, "-");
}
city = $("#city").val();
if(keyword.length>0){
city = city.subString(0,(city.length-1));
city = city.replace(/, /g, "-");
city = city.replace(/ /g, "-");
}
window.location.href = "<?php echo base_url(); ?>" + keyword + "-in-" + city;
});