Question

我不知道如何在sql数据库中打印某个属性的标题，不知道为什么它向我输出了查询语句，我需要您的帮助。以下是我的php代码：

<?php
/* getting the last record */
$con=mysqli_connect("localhost","root","","task");
$t="SELECT * FROM note ORDER BY id DESC LIMIT 1";
$thetitle="SELECT title FROM note ORDER BY id DESC LIMIT 1";
if(mysqli_query($con, $thetitle)){
mysqli_query($con,$thetitle);
echo ("<button class='call_modal' style='cursor:pointer;'>$thetitle</button>");
}
?>

Answer 1

希望对您有帮助

$query = "SELECT title FROM note ORDER BY id DESC LIMIT 1";

// Perform query
// For successful SELECT queries it will return a mysqli_result object
// For other successful queries it will return TRUE. FALSE on failure
$result = mysqli_query($con, $query);

// Fetch result row as an associative array:
// Note: Fieldnames returned from this function are case-sensitive.
$row = mysqli_fetch_assoc($result);

// Check if any result row was returned
if($row){
    echo '<button class="call_modal" style="cursor:pointer;">'. $row['title'] . '</button>';
}

Answer 2

请检查下面的代码

<?php
    /* getting the last record */
    $con = mysqli_connect("localhost","root","","task");
    $t = "SELECT * FROM note ORDER BY id DESC LIMIT 1";
    $thetitle = "SELECT title FROM note ORDER BY id DESC LIMIT 1";
       if(mysqli_query($con, $thetitle)){

           $result = mysqli_query($con,$thetitle); // run query and store the result in result variable 

           while ($row= mysqli_fetch_assoc($result)){ // fetch the result set
                       echo "<button class='call_modal' style='cursor:pointer;'>".$row['title']."</button>";
                 } 


        }
    ?>

为什么它不断回显查询语句？

2 个答案: