Question

我使用此代码将t = 0.000000替换为一个计数器（时间= time + 10），因此每次代码找到t = 0.000000时，它将加10并变为0、10、20，... 任何想法如何做到这一点

import re
import itertools
counter = itertools.count(0, 10)
with open("input.txt", "r") as f_in:
with open("output.txt", "w") as f_out:
    for line in f_in:
        re.sub("t=0.000000", f"t={next(counter):.6f}", line.lower())
        f_out.write(line + "/n")

Answer 1

您可能想要这样的东西：

import re
import itertools
counter = itertools.count(0, 10)
with open("input.txt", "r") as f_in:
    with open("output.txt", "w") as f_out:
        for line in f_in:
            re.sub("t=0.000000", f"t += {next(counter)}", line.lower())
            f_out.write(line + "/n")

count给出10的倍数的无穷序列，用sub替换旧的部分为新的部分。

编辑：

只是注意到您想要不同的输出，因此相应地更改了字符串：

import re
import itertools
counter = itertools.count(0, 10)
with open("input.txt", "r") as f_in:
    with open("output.txt", "w") as f_out:
        for line in f_in:
            re.sub("t=0.000000", f"t={next(counter):.6f}", line.lower())
            f_out.write(line + "/n")

通过计算时间来代替t = 0.000000

1 个答案: