Laravel后函数参数

Question

我有一些代码

        $validator->after(function ($validator) {

        var_dump($request->input('answer'));

        if (true) {
            $validator->errors()->add('Question', 'The answer is not correct!');
        }
    });

但是我遇到了需要向下传递$ request-> input（'answer'）的问题。它给我一个错误，未定义$ request。我该怎么办？

Answer 1

    public function contact(Request $request) {

    $validator = Validator::make($request->all(), [
        'id' => 'required',
        'boat' => 'required',
        'name' => 'required',
        'answer' => 'required',
        'email' => 'required|email',
        'message' => 'required'
    ]);


   if ((int)$request->input('answer') != $request->session()->get('contact-seller-answer')) {
   }
    $validator->after(function ($validator, **$request**) {

        var_dump($request->input('answer'));

        if (true) {
            $validator->errors()->add('Question', 'The answer is not correct!');
        }
    });


    if ($validator->fails()) {
        return redirect('ad/'.$request->input('id').'/'.$request->input('boat').'#form')
                    ->withErrors($validator)
                    ->withInput($request->all());
    }
}