在订单表中插入时会遇到此错误
org.springframework.dao.InvalidDataAccessApiUsageException: detached entity passed to persist: org.vi.entities.LineItem; nested exception is org.hibernate.PersistentObjectException: detached entity passed to persist: org.vi.entities.LineItem
映射 这就是我映射课程的方式:
@Entity
public class Order implements Serializable {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name = "id", updatable = false, nullable = false)
private Long id;
@Column(name = "delivered", nullable = false)
private boolean delivered;
@OneToMany(cascade = CascadeType.ALL, orphanRemoval = true)
@JoinColumn(name = "fk_order")
private Set<LineItem> lineItems= new HashSet<LineItem>();
}
@Entity
public class LineItem implements Serializable {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name = "id", updatable = false, nullable = false)
private Long id;
@Column(name="quantity", nullable = false)
private int quantity;
@ManyToOne
private Product product;
}
@Entity
public class Product implements Serializable {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name = "id", updatable = false, nullable = false)
private Long id;
@Column(name = "reference", unique = true, nullable = false)
private String reference;
@Column(name = "price", nullable = false)
private double price;
}
插入我的表格 这就是我在表格中保存新行的方式
Product p1 = new Product("reference1",10000);
Product p2 = new Product("reference2",20000;
productRepository.save(p1);productRepository.save(p2);
LineItem li1 = new LineItem(6, p1);
LineItem li1 = new LineItem(9, p2);
lineItemRepository.save(li1);lineItemRepository.save(li2);
Set<LineItem> lineItems1= new HashSet<LineItem>();
lineItems1.add(li1);
lineItems1.add(li2);
Order o1 = new Order(false,lineItems1);
orderRepository.save(o1);
如果映射有问题,请您帮我吗?
答案 0 :(得分:1)
尝试以下方法:
Order o1 = new Order(false,lineItems1);
o1.getLineItems().add(new LineItem(6, p1););
o1.getLineItems().add(new LineItem(6, p1););
orderRepository.save(o1);
不是创建新的HashSet,而是使用现有的from顺序的HashSet,因为这是hibernate跟踪的对象。
答案 1 :(得分:0)
我认为您应该尝试删除lineItemRepository.save(li1);lineItemRepository.save(li2);
行,因为CascadeType.ALL
还将保留Set<LineItem>
。
答案 2 :(得分:0)
替换此代码,
LineItem li1 = new LineItem(6, p1);
LineItem li2 = new LineItem(9, p2);
lineItemRepository.save(li1);lineItemRepository.save(li2);
如有任何问题,请告知。