Question

我有以下表格：

thread: id, title, content, created
thread_tags: tag_id, thread_id
tag: id, name
author_threads: thread_id, author_id

我通常会将值插入所有这些字段（为简单起见，省略了一些步骤）：

  $sql_thread = "INSERT INTO thread (title, content)
           VALUES ('some title', 'some content')";

   #  this is normally a loop, as there are more than one tags:   
   $sql_tags = "INSERT INTO tag (name) 
               VALUES ('onetag')";


   #  normally I would check the return value
   mysqli_query($link, $sql_thread);

   #  get the thread id:
   $thread_id = mysqli_insert_id($link);

   mysqli_query($link, $sql_tags);

   #  get the tag id:
   $tag_id = mysqli_insert_id($link);

   #  insert into thread_tags:
   mysqli_query($link, "INSERT INTO thread_tags (thread_id, tag_id)  VALUES ($thread_id, $tag_id)");

   #  insert into author_threads, I already know author_id:
   mysqli_query($link, "INSERT INTO author_threads (author_id, thread_id)  VALUES ($author_id, $thread_id)")

我想确保所有这些都发生或者没有发生（即创建线程的过程）。如何编写此代码以使用事务？或者以其他方式确保所有这些都发生？

Answer 1

将您的表格转换为innodb（如果它们尚未存在）
在所有查询之前执行mysqli_autocommit($link, FALSE);
在所有查询后执行mysqli_commit($link);，如果他们已成功执行
如果任何查询失败 - 执行mysqli_rollback($link);并停止执行

更多详情：

PHP事务和mysqli_insert_id

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