数据透视后,我无法汇总表(SQL-Server)中的数字,我将非常感谢您的建议。
如果我在示例中解释问题,更好:
现有表格:
+-------+-----------+-----------+-------------------+
| # | $$$$$ | Fire | Water |
+-------+-----------+-----------+-------------------+
| 1 | 5 | 1 | 5 |
| 1 | 4 | 1 | 5 |
| 1 | 10 | 1 | 5 |
| 2 | 3 | 3 | 8 |
| 2 | 4 | 3 | 8 |
+-------+-----------+-----------+-------------------+
所需的输出:
+-------+-----------+-----------+-------------------+
| # | $$$$$ | Fire | Water |
+-------+-----------+-----------+-------------------+
| 1 | 19 | 1 | 5 |
| 2 | 7 | 3 | 8 |
+-------+-----------+-----------+-------------------+
我倾向于认为我已经尝试过使用汇总和分组找到的所有解决方案,但是并没有解决,因此我依靠您。提前致谢。我用来创建表格的代码:
WITH Enerc AS
(
SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
FROM
data1 AS a1
LEFT JOIN
data2 AS a2 ON a1.[id] = a2.[id]
)
SELECT *
FROM Enerc
PIVOT
(SUM(gross_claim) FOR [cause_of_loss] IN ([Fire], [Water])) AS PivotTable;
答案 0 :(得分:2)
无需旋转。您应该通过分组并使用SUM
来获得所需的结果:
SELECT
a1.[#],
SUM(a1.[$$$$$]),
a1.[Fire]
a1.[Water]
from data1 as a1
group by a1.[#], a1.[Fire], a1.[Water]
让我展示一个例子:
DECLARE @Hello TABLE
(
[#] INT,
[$$$$$] INT,
[Fire] INT,
[Water] INT
)
INSERT INTO @Hello
(
#,
[$$$$$],
Fire,
Water
)
VALUES
( 1, -- # - int
5, -- $$$$$ - int
1, -- Fire - int
5 -- Water - int
)
, (1, 4, 1, 5)
, (1, 10, 1, 5)
, (2, 3, 3, 8)
, (2, 4, 3, 8)
SELECT
h.#,
SUM(h.[$$$$$]),
h.Fire,
h.Water
FROM @Hello h
GROUP BY h.#, h.Fire, h.Water
答案 1 :(得分:0)
在数据透视后尝试分组。
With Enerc as
(SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
from data1 as a1
left join data2 as a2
on a1.[id] = a2.[id]
)
select *
into tmp
from Enerc
PIVOT
(sum(gross_claim)
FOR [cause_of_loss] in (
[Fire], [Water]))
as PivotTable
select [#], sum([$$$$$])as [$$$$$], Fire, Water
from #tmp
group by [#],Fire, Water
编辑:在权限被拒绝的情况下:
With Enerc as
(SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
from data1 as a1
left join data2 as a2
on a1.[id] = a2.[id]
),phase2 as(
select *
from Enerc
PIVOT
(sum(gross_claim)
FOR [cause_of_loss] in (
[Fire], [Water]))
as PivotTable)
select [#], sum([$$$$$])as [$$$$$], Fire, Water
from phase2
group by [#],Fire, Water