Question

不使用ORM，如何将NOT IN子查询附加到SELECT查询？

public function testFoo()
{
    $faker = Faker\Factory::create();
    $response = $this->call('POST', route('make.foo'), [
        'content' => $faker->text(200),
    ]);
    $response->assertRedirect('/');
}

使用Python：

public class Alpha_Loop extends AppCompatActivity {

ImageView abc,img1;
int i = 0;
int ab;
int playsound;
Runnable Rn;
int s = 0;
long updatetime;
MediaPlayer mediaPlayer;
Handler handler;
//Array of Image1
final int[] ImageArray = {R.drawable.a, R.drawable.a, R.drawable.b, R.drawable.c, R.drawable.d, R.drawable.e,
        R.drawable.f, R.drawable.g, R.drawable.h, R.drawable.i, R.drawable.j, R.drawable.k,
        R.drawable.l, R.drawable.m, R.drawable.n, R.drawable.o, R.drawable.p, R.drawable.q,
        R.drawable.r, R.drawable.s, R.drawable.t, R.drawable.u, R.drawable.v, R.drawable.w,
        R.drawable.x, R.drawable.y, R.drawable.z};

//Array of Image1
final int[] img1Array = {R.drawable.apple, R.drawable.ball, R.drawable.cat, R.drawable.dog, R.drawable.egg,
        R.drawable.fish, R.drawable.goat, R.drawable.hat, R.drawable.insect, R.drawable.jar,
        R.drawable.king, R.drawable.leaf, R.drawable.monkey, R.drawable.nose, R.drawable.ocean,
        R.drawable.parrot, R.drawable.queen, R.drawable.rat, R.drawable.sun, R.drawable.tap,
        R.drawable.umbrella, R.drawable.violin, R.drawable.well, R.drawable.box, R.drawable.yatch,
        R.drawable.zebra};
//Array of wav files
final int[] Soundid = {R.raw.a, R.raw.a, R.raw.b, R.raw.c, R.raw.d, R.raw.e,
        R.raw.f, R.raw.g, R.raw.h, R.raw.i, R.raw.j, R.raw.k,
        R.raw.l, R.raw.m, R.raw.n, R.raw.o, R.raw.p, R.raw.q,
        R.raw.r, R.raw.s, R.raw.t, R.raw.u, R.raw.v, R.raw.w,
        R.raw.x, R.raw.y, R.raw.z};

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.alpha__loop);
    abc = findViewById(R.id.abc);
    img1 = findViewById(R.id.img1);
    aa();

}
public void aa(){

    final Handler handler = new Handler();
    Rn = new Runnable() {
        @Override
        public void run() {
            abc.setImageResource(ImageArray[ab]);
            ab++;
            if (i == ImageArray.length) {
                i = 0;
            }
            img1.setImageResource(img1Array[i]);
            i++;
            if (i == img1Array.length) {
                i = 0;
            }
            playsound = Soundid[s];
            mediaPlayer = MediaPlayer.create(Alpha_Loop.this, Soundid[s]);
            s++;
            mediaPlayer.setOnPreparedListener(new MediaPlayer.OnPreparedListener() {
                @Override
                public void onPrepared(MediaPlayer mp) {
                    mediaPlayer.start();
                }
            });
            mediaPlayer.start();
            updatetime =  mediaPlayer.getDuration();
            if (s >= Soundid.length) {
                s = 0;
            }
        }
    };
    handler.postDelayed(Rn, updatetime);

}

}

我总是可以恢复为原始sql，但这将是轻松的出路;-）。

Answer 1

benvc给出了正确答案：

select([table_a]).where(table_a.c.id.notin_(select([table_b.c.id])))

SQLAlchemy（核心）NOT IN子查询

1 个答案: