这是我的代码:
from sympy import symbols, Equivalent
from sympy.logic.boolalg import to_cnf as fnc, Implies, to_cnf
from sympy.abc import a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, v, w, x, y, z
def eq(a, b):
return fnc(Equivalent(a, b), True)
inr = str(input('Enter formula: '))
x = ' '
for i in inr:
#print(inr[inr.index(i-2)])
if i == '>':
i = '>>'
x += i
elif i == '=':
print(i)
i = 'Equivalent'
x += i
else:
x += i
print(fnc(x, True))
我要输入input =(a,b)
而不是Equivalent function
来呼叫(a=b)
。我怎样才能做到这一点?
我尝试控制=
的上一个和下一个元素,并在输入(a = b)时将其添加到Equivalent
函数中,输出应为(a|~b)&(b|~a)
,但它不起作用。
i= sympy.Equivalent(symbols((inr[inr.index(i) - 1])), symbols(inr[inr.index(i) + 1]))
答案 0 :(得分:0)
因此,根据您的示例I / O:
IN :因此,当您输入(a = b)时,输出应为? – user5173426
OUT :应该是(a |〜b)&(b |〜a)– Yacine Benatia
我对您现有的代码进行了一些更改:
from sympy import symbols, Equivalent
from sympy.logic.boolalg import to_cnf as fnc, Implies, to_cnf
from sympy.abc import a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, v, w, x, y, z
def eq(a, b):
return fnc(Equivalent(a, b), True)
inr = str(input('Enter formula: '))
x = ' '
# get the part of the formula/string before =
y = inr.rsplit('=', 1)[0]
# get the part of the formula/string after =
z = inr.rsplit('=', 1)[1]
for i in inr:
if i == '>':
i = '>>'
x += i
elif i == '=':
i = 'Equivalent'
x = i
elif i != ')':
x += y
x += ','
x += z
# print(x)
print(fnc(x, True))
输出: