Question

当我遍历字典元素并将它们添加到列表中时。在这里，我需要根据关键元素选择“项目”并将其存储到列表中。

  {"0":["1234","2222","4321","211000","90024","12","2121","322223","2332","3232"],"1":["0856","6040222","175002","23572","","","","","",""]}

    List<string> strlist;
    strlist = new List<string>();

    var jr = JsonConvert.DeserializeObject<Dictionary<string, List<string>>>(paramValue);

    foreach (var item in jr)
    {
      // Need to add item on basis of Key
      // Can we include any where clause
       strlist.AddRange(item.Value);
    }

谢谢

Answer 1

如果我了解Need to add item on basis of Key的正确含义，那么它应该对您有用：

List<string> strlist = new List<string>();
var jr = JsonConvert.DeserializeObject<Dictionary<string, List<string>>>(paramValue);

foreach (var item in jr)
{
  if(item.Key == "someKey")
  {
      strlist.AddRange(item.Value);
  }
}

或者如果您有多个键要匹配：

List<string> strlist = new List<string>();
var jr = JsonConvert.DeserializeObject<Dictionary<string, List<string>>>(paramValue);
List<string> targetKeys = new List<string>{"someKey", "anotherKey", "oneAwesomeKey"};

foreach (var item in jr)
{
  if(targetKeys.Contains(item.Key))
  {
      strlist.AddRange(item.Value);
  }
}

这里的第一个示例显示仅当键等于定义的字符串（在此示例中为someKey）时添加字典值。第二个示例显示了如果字典键包含在已定义的字符串列表中，则添加字典值。

您还可以使用linq实现此目标，如下所示：

var jr = JsonConvert.DeserializeObject<Dictionary<string, List<string>>>(paramValue);

var strlist= jr.Where(x => x.Key == "someKey").SelectMany(x => x.Value).ToList();

同样可以匹配多个键：

var jr = JsonConvert.DeserializeObject<Dictionary<string, List<string>>>(paramValue);
List<string> targetKeys = new List<string>{"someKey", "anotherKey", "oneAwesomeKey"};

var strlist= jr.Where(x => targetKeys.Contains(x.Key)).SelectMany(x => x.Value).ToList();

遍历字典元素并将其添加到列表中

1 个答案: