Question

我想知道HtmlAgilityPack读取包含xsl文件来呈现html的xml文件的最佳方法。 HtmlDocument类上是否有任何设置可以帮助解决这个问题，或者在使用HtmlAgiliyPack加载转换之前是否必须找到执行转换的方法？如果对后者是肯定的，那么任何人都知道这种转变的好库或方法吗？下面是一个使用xls文件返回xml的网站示例以及我想要使用的代码。

var uri = new Uri("http://www.skechers.com/");
var request = (HttpWebRequest)WebRequest.Create(url);
var cookieContainer = new CookieContainer();

request.CookieContainer = cookieContainer;
request.UserAgent = @"Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5";
request.Method = "GET";
request.AllowAutoRedirect = true;
request.Timeout = 15000;

var response = (HttpWebResponse)request.GetResponse();
var page = new HtmlDocument();
page.OptionReadEncoding = false;
var stream = response.GetResponseStream();
page.Load(stream);

这段代码不会抛出任何错误，但是xml是被解析的而不是转换，这就是我想要的。

Answer 1

Html Agility Pack可以在两点帮助您：

1）使用它获取Xml处理指令更容易，因为它将PI数据解析为Html，因此它会将其转换为属性

2）HtmlDocument实现IXPathNavigable，因此可以通过.NET Xslt转换引擎直接转换。

这是一段有用的代码。我必须添加一个特定的XmlResover来正确处理Xslt转换，但我认为这是特定于这个skechers的情况。

public static void DownloadAndProcessXml(string url, string userAgent, string outputFilePath)
{
    using (XmlTextWriter writer = new XmlTextWriter(outputFilePath, Encoding.UTF8))
    {
        DownloadAndProcessXml(url, userAgent, writer);
    }
}

public static void DownloadAndProcessXml(string url, string userAgent, XmlWriter output)
{
    UserAgentXmlUrlResolver resolver = new UserAgentXmlUrlResolver(url, userAgent);

    // WebClient is an easy to use class.
    using (WebClient client = new WebClient())
    {
        // download Xml doc. set User-Agent header or the site won't answer us...
        client.Headers[HttpRequestHeader.UserAgent] = resolver.UserAgent;
        HtmlDocument xmlDoc = new HtmlDocument();
        xmlDoc.Load(client.OpenRead(url));

        // determine xslt (note the xpath trick as Html Agility Pack does not support xml processing instructions)
        string xsltUrl = xmlDoc.DocumentNode.SelectSingleNode("//*[name()='?xml-stylesheet']").GetAttributeValue("href", null);

        // download Xslt doc
        client.Headers[HttpRequestHeader.UserAgent] = resolver.UserAgent;
        XslCompiledTransform xslt = new XslCompiledTransform();
        xslt.Load(new XmlTextReader(client.OpenRead(url + xsltUrl)), new XsltSettings(true, false), null);

        // transform Html/Xml doc into new Xml doc, easy as HtmlDocument implements IXPathNavigable
        // note the use of a custom resolver to overcome this Xslt resolve requests
        xslt.Transform(xmlDoc, null, output, resolver);
    }
}

// This class is needed during transformation otherwise there are errors.
// This is probably due to this very specific Xslt file that needs to go back to the root document itself.
public class UserAgentXmlUrlResolver : XmlUrlResolver
{
    public UserAgentXmlUrlResolver(string rootUrl, string userAgent)
    {
        RootUrl = rootUrl;
        UserAgent = userAgent;
    }

    public string RootUrl { get; set; }
    public string UserAgent { get; set; }

    public override object GetEntity(Uri absoluteUri, string role, Type ofObjectToReturn)
    {
        WebClient client = new WebClient();
        if (!string.IsNullOrEmpty(UserAgent))
        {
            client.Headers[HttpRequestHeader.UserAgent] = UserAgent;
        }
        return client.OpenRead(absoluteUri);
    }

    public override Uri ResolveUri(Uri baseUri, string relativeUri)
    {
        if ((relativeUri == "/") && (!string.IsNullOrEmpty(RootUrl)))
            return new Uri(RootUrl);

        return base.ResolveUri(baseUri, relativeUri);
    }
}

你这样称呼它：

    string url = "http://www.skechers.com/";
    string ua = @"Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5";
    DownloadAndProcessXml(url, ua, "skechers.html");

Answer 2

您应该呈现XML和XSLT的输出。为此，您需要下载XML，并且您已经完成了。接下来解析XML以标识XSL引用。然后，您需要下载XSL并将其应用于XML文档。

这些链接可能很有用

Answer 3

这是我收到回复后最终使用的附加代码。请注意，只有在响应为＆＃34; application / xml＆＃34;并且您必须检查整个对象的空实例。此外，FormAssetSrc是一个私有函数，它接受href的值并确定它是协议，根或文档相对，并创建完全限定的uri。

var xmlStream = response.GetResponseStream();
var xmlDocument = new XPathDocument(xmlStream);
var styleNode = xmlDocument.CreateNavigator().SelectSingleNode("processing-instruction('xml-stylesheet')");
var hrefValue = Regex.Match((styleNode).Value, "href=(\"|')(?<url>.*?)(\"|')");
if(hrefValue.Success)
{
    var xslHref = FormAssetSrc(hrefValue.Groups["url"].Value, response.ResponseUri);
    var xslUri = new Uri(xslHref);
    var xslRequest = CreateWebRequest(xslUri);
    var xslResponse = (HttpWebResponse)xslRequest.GetResponse();
    var xslStream = new XPathDocument(xslResponse.GetResponseStream());
    var xslTransorm = new XslTransform();
    var sw = new System.IO.StringWriter();
    xslTransorm.Load(xslStream);
    xslTransorm.Transform(xmlDocument.CreateNavigator(), null, sw);
    page.Html.LoadHtml(sw.ToString());
}

HtmlAgilityPack可以处理xsl文件附带的xml文件来呈现html吗？

3 个答案: