Question

当我将异步函数定义为：

module.exports.sendSmtpMessage = async function(keys, mailOptions) {  // <== warning
    await sendSmtpMessage(keys, mailOptions);
}

var sendSmtpMessage = async function(keys, mailOptions) {
...
}

update2

var sendMessage = async function sendMessage(keys, mailOptions) {
...
}

module.exports.sendSmtpMessage = async function sendSmtpMessage(keys, mailOptions) {
    await sendMessage(keys, mailOptions);
}

我收到警告：

19:34  warning  Unexpected unnamed async function                          func-names

写得不好吗？

感谢您的反馈

****更新1 **。根据Ankit的评论.. **。

module.exports.sendSmtpMessage = async function sendSmtpMessage(keys, mailOptions) {  // <== warning
    await sendSmtpMessage(keys, mailOptions);
}

var sendSmtpMessage = async function(keys, mailOptions) { // <== warning and error !
...
}

23:7   error    'sendSmtpMessage' is assigned a value but never used  no-unused-vars
23:25  warning  Unexpected unnamed async function

解决一个警告，现在得到一个警告+ 1个错误...

更新2 。需要更改定义的顺序并使用...没有更多的警告或错误...

var sendMessage = async function sendMessage(keys, mailOptions) {
...
}

module.exports.sendSmtpMessage = async function sendSmtpMessage(keys, mailOptions) {
    await sendMessage(keys, mailOptions);
}

Answer 1

要摆脱该错误，您可以为async函数命名，例如：

var sendSmtpMessage = async function sendSmtpMessage(keys, mailOptions)

Answer 2

具有命名导出功能可以轻松组织代码。

const doSomething = async function(args) {
  // ...
}

const doSomethingElse = async function() {
    await doSomething(args);
}

module.exports = {
  doSomething: doSomething,
  doSomethingElse: doSomethingElse
}

Answer 3

正确命名，带有命名函数：先定义然后导出...

const sendMessage = async function sendMessage(keys, mailOptions) {
    ....
};

module.exports.sendSmtpMessage = async function sendSmtpMessage(keys, mailOptions) {
  await sendMessage(keys, mailOptions);
};

eslint警告意外的未命名异步函数，是否要摆脱它？

3 个答案: