Question

嘿，我正在寻找从列表中打印单词和数字的人。它将包含一个名称列表，然后是年龄的单独列表。我希望将其打印到我用递归打印矩形制作的“ excel”外观文档中。在理想的情况下，我可以组织每个require字段的列表，并可能使用一个循环，告诉它在某个x位置开始打印，并在循环中将每个单词向下打印某个x，从而轻松地填充行。任何帮助，将不胜感激。我曾尝试为这种情况专门寻找一些打印代码，但找不到任何代码。谢谢！

import pygame
pygame.font.init()
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
font = pygame.font.SysFont("Arial", 25, True, False)




def main():
    def recursive_draw(x, y, width, height):
        """Recursive rectangle function."""
        pygame.draw.rect(screen, BLACK, [x, y, width, height], 1)
        if y >= 600:  # Screen bottom reached.
            return
        # Is the rectangle wide enough to draw again?
        elif x < 750 - width:  # Right screen edge not reached.
            x += width
            # Recursively draw again.
            recursive_draw(x, y, width, height)
        else:
            # Increment y and reset x to 0 and start drawing the next row.
            x = 0
            y += height
            recursive_draw(x, y, width, height)

    pygame.init()
    size = [750, 550]
    screen = pygame.display.set_mode(size)
    clock = pygame.time.Clock()
    screen.fill(WHITE)
    recursive_draw(0, 0, 150, 50)

    done = False
    while not done:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                done = True



        pygame.display.flip()
        clock.tick(60)


main()

pygame.quit()

Answer 1

只需遍历数据，并为每个单元格增加y，然后为每行增加x。

这是它的样子：

import pygame
import pygame.freetype

def recursive_draw(surf, x, y, width, height):
    """Recursive rectangle function."""
    pygame.draw.rect(surf, (0, 0, 0), [x, y, width, height], 1)
    if y >= 600:  # Screen bottom reached.
        return
    # Is the rectangle wide enough to draw again?
    elif x < 750 - width:  # Right screen edge not reached.
        x += width
        # Recursively draw again.
        recursive_draw(surf, x, y, width, height)
    else:
        # Increment y and reset x to 0 and start drawing the next row.
        x = 0
        y += height
        recursive_draw(surf, x, y, width, height)

data = [
    (1, 'RED',    23, 'dog',   41),
    (2, 'BLUE',   12, 'cat',   42),
    (3, 'YELLOW', 12, 'horse', 43),
    (4, 'GREEN',  99, 'bear',  55),
    (5, 'CYAN',   52, 'snake', 14)
]

def main():

    pygame.init()
    font = pygame.freetype.SysFont("Arial", 25, True, False)
    size = [750, 550]
    screen = pygame.display.set_mode(size)
    clock = pygame.time.Clock()
    screen.fill((255, 255, 255))
    background = screen.copy()
    recursive_draw(background, 0, 0, 150, 50)

    while True:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                return

        screen.blit(background, (0, 0))

        # let's have a padding of 15px inside the cell
        x = 15
        y = 15
        for row in data:
            for cell in row:
                font.render_to(screen, (x, y), str(cell), pygame.Color('dodgerblue'))
                x += 150 # should be a constant
            y += 50 # should be a constant
            x = 15 # should be a constant, too :-)

        pygame.display.flip()
        clock.tick(60)


if __name__ == '__main__':
    main()
    pygame.quit()

您可以使用相同的方法来绘制矩形，因此不需要递归函数。嵌套循环就足够了。

要读取这样的文件（data.txt）：

1, 'RED',    23, 'dog',   41
2, 'BLUE',   12, 'cat',   42
3, 'YELLOW', 12, 'horse', 43
4, 'GREEN',  99, 'bear',  55
5, 'CYAN',   52, 'snake', 14

导入csv模块并使用

data = []
with open('data.txt', newline='') as csvfile:
    reader = csv.reader(csvfile, quotechar="'", skipinitialspace=True)
    for row in reader:
        data.append(row)

代替

data = [
    (1, 'RED', 23, 'dog',   41),
    ...
]

从列表中打印单词到pygame中的特定坐标

1 个答案: