Question

我一直在为我做一个乌龟矿的程序。在这里：

local depth = 0
local isJunk = true

function fuel()
    if turtle.getFuelLevel() < 20 then
        turtle.select(16)
        turtle.refuel(1)
    end
end
function up()
    fuel()
    if turtle.up() then
        return true
        depth = depth - 1
    else
        return false
    end
end
function down()
    fuel()
    if turtle.down() then
        return true
        depth = depth + 1
    else
        return false
    end
end
function checkWalls()
    for i = 1,4 do
        for j = 1,6 do
            turtle.select(i)
            if turtle.compare() then
                isJunk = true
            end
        end
        if isJunk == false then
            turtle.dig()
        end
        turtle.turnLeft()
    end
end
function digDown()
    for k = 1,6 do
        turtle.select(k)
        if turtle.compareDown() then
            if turtle.digDown() then
                return true
            else
                return false
            end
        end
    end
    turtle.select(1)
    turtle.digDown()
end
function digUp()
    for l = 1,6 do
        turtle.select(l)
        if turtle.compareUp() then
            if turtle.digUp() then
                return true
            else
                return false
            end
        end
    end
    turtle.select(1)
    turtle.digUp()
end

while true do
    term.clear()
    term.setCursorPos(1,1)
    print("-------Mining Operation Alpha-------")
    term.setCursorPos(1,2)
    term.write("Commence Mining Operation? (y/n): ")

    local input = read()

    if input  == "n" then
        term.setCursorPos(1,3)
        print("Cancelling Operation")
        sleep(1)
        exit()
    elseif input == "y" then
        term.setCursorPos(1,3)
        print("Commencing Alpha Mine")
        sleep(1)
     end

    digDn()
    down()
    digDn()
    down()
    turtle.select(7)
    turtle.placeUp()
    checkWalls()
    digDn()
    while down() do
        checkWalls()
        digDn()
    end
    up()
    turtle.select(15)
    turtle.placeDown()
    for m = 1,5 do
        up()
    end
    turtle.dig()
    fuel()
    turtle.forward()
    turtle.dig()
    fuel()
    turtle.forward()
    turtle.turnRight()
    turtle.dig()
    fuel()
    turtle.forward()
    turtle.turnLeft()
    digDn()
    while down() do
        digdn()
    end
    checkWalls()
    up()
    turtle.select(15)
    turtle.placeDown()
    checkWalls()
    while depth > 1 do
        digUp()
        up()
        checkWalls()
    end
    digUp()
    up()
    up()
    turtle.select(7)
    turtle.placeDown()
    fuel()
    turtle.forward()
    turtle.forward()
    turtle.turnRight()
    turtle.forward()
    turtle.turnLeft()
end

第1至第6个插槽是我不想开采的物品，第7个是鹅卵石，第15个是火把，所以小怪不会在井筒底部产卵，第16个是煤。

无论何时运行它，我都会收到一条错误消息：

bios.lua:26: [string "mine.lua"]:14: 'end' expected (to close 'if' at line 12)

我查看了一下，该陈述有一个“结尾”。但是，如果我注释掉返回函数，它将起作用。如果有人知道解决方案或漏洞来完成这项工作，我将不胜感激。预先感谢！

Answer 1

return语句必须是块中的最后一条语句。

您可能想要

function up()
    fuel()
    if turtle.up() then
        depth = depth - 1
        return true
    else
        return false
    end
end

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