Question

好的，所以我已经为这个Java类中的最终项目构建了此代码。给出的说明如下：

选项2：监控系统   作为动物园管理员，重要的是要了解您所照看的动物的活动并监视它们的生活环境。创建一个执行以下所有操作的监视系统：

向用户询问是否要监视动物，监视栖息地或退出   显示从动物或栖息地文件中读取的动物/栖息地选项列表（基于先前的选择）

要求用户输入选项之一



通过在文件中找到适当的部分来显示监视信息



按类别和选择（例如“动物-狮子”或“栖息地-企鹅”）分隔各个部分



如果监视器检测到超出正常范围的内容，则使用对话框警告动物园管理员（这些将在文件中用新行表示   从...开始 *****。不要在对话框中显示星号。）



允许用户返回到原始选项

我开发的代码如下：

import java.util.Scanner;



public class Final {


static final Scanner scan = new Scanner(System.in);


public static void main(String args[]) {

    System.out.println("Menu:");

    System.out.println("Monitor Animal");

    System.out.println("Monitor Habitat");

    System.out.println("Exit");



Scanner input1 = new Scanner(System.in);

String userInput1 = input1.nextLine();



    if (userInput1.equals("Monitor Animal")); {

        System.out.println("Details on lions");

        System.out.println("Details on tigars");

        System.out.println("Details on bears");

        System.out.println("Details on giraffes");

        System.out.println("Exit");



        Scanner input2 = new Scanner(System.in);

        String userInput2 = input2.nextLine();



        switch(userInput2) {

            case 1: userInput2 = "Details on lions";

                System.out.println("Animal - Lion");

                System.out.println("Name: Leo");

                System.out.println("Age: 5");

                System.out.println("Health concerns: Cut on left front paw");

                System.out.println("Feeding schedule: Twice daily");

                break;



            case 2: userInput2 = "Details on tigers";

                System.out.println("Animal - Tigar");

                System.out.println("Name: Maj");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: 3x daily");

                break;



            case 3: userInput2 = "Details on bears";

                System.out.println("Animal - Bear");

                System.out.println("Name: Baloo");

                System.out.println("Age: 1");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: None on record");

                break;



            case 4: userInput2 = "Details on giraffes";

                System.out.println("Animal - Giraffe");

                System.out.println("Name: Spots");

                System.out.println("Age: 12");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: Grazing");

                break;



            case 5: userInput2 = "Exit";

                break;



            default: userInput2 = System.out.println("Error: Invalid Animal");

                break;

            }



    if (userInput1.equals("Monitor Habitat")); {

        System.out.println("Details on penguin habitat");

        System.out.println("Details on bird house");

        System.out.println("Details on aquarium");

        System.out.println("Exit");



        Scanner input3 = new Scanner(System.in);

        String userInput3 = input3.nextLine();



        switch(userInput3) {



            case 1: userInput3 = "Details on penguin habitat";

                System.out.println("Habitat - Penguin");

                System.out.println("Temperature: Freezing");

                System.out.println("Food source: Fish in water running low");

                System.out.println("Cleanliness: Passed");

                break;



            case 2: userInput3 = "Details on bird house";

                System.out.println("Habitat - Bird");

                System.out.println("Temperature: Moderate");

                System.out.println("Food source: Natural from environment");

                System.out.println("Cleanliness: Passed");

                break;



            case 3: userInput3 = "Details on aquarium";

                System.out.println("Habitat - Aquarium");

                System.out.println("Temperature: Varies with output temperature");

                System.out.println("Food source: Added daily");

                System.out.println("Cleanliness: Needs cleaning from algae");

                break;



            case 4: userInput3 = "Exit";

                break;



            default: System.out.println("Error: Invalid Habitat");

                break;
    }



    if (userInput1.equals("Exit")); {

        System.out.println("Goodbye!");


    }

  }
}

它无法编译，我无法弄清楚我在做什么错。有一个更好的方法吗？我已经尝试了一天半，现在大约需要3个小时。任何帮助将不胜感激！

Answer 1

您正在执行的 if-else 语句的格式是错误的。表达式后不提供分号。格式为

 if(expression){
 //statement

 }

Answer 2

在switch语句中，您正在将int与字符串进行比较。因此，您应该将字符串与字符串进行比较。例如，在您的代码中：

Scanner input2 = new Scanner(System.in);
    String userInput2 = input2.nextLine();
    switch(userInput2) {

        case "Details on lions":
            System.out.println("Animal - Lion");
            System.out.println("Name: Leo");
            System.out.println("Age: 5");
            System.out.println("Health concerns: Cut on left front paw");
            System.out.println("Feeding schedule: Twice daily");
            break;

Answer 3

if上没有分号（示例）；

只需输入

if(){ 
} // simple as that.

您的开关盒也有问题。需要成为

 case 'Details on penguin habitat':
 break;

 case 'Details on bird house':
 break

Java Final Project动物监控系统

3 个答案: