Question

我正在制作一个基本程序来计算字符串的元音。现在，我想尝试使用布尔函数，因为我感觉很喜欢，但是每当我用元音输入字符串时，它都不会增加vowel的整数。

其中有一个错误，但我找不到它。

#include <iostream>

using namespace std;

bool isVowel(char){
char chara;
return (chara == 'A' || chara == 'E' || 
chara == 'I' || chara == 'O' || chara == 'U' || chara == 'Y' || chara == 'a' || chara == 'e' || chara == 'i' || chara == 'o' || chara == 'u' || chara == 'y');
}

int main()
{
string input;
int vowels = 0;

cout << "Vowel checker v1.0.0\n";
cout << "Type the word that you want to count the vowels of.\n";
cin >> input;

for(unsigned int i = 0; i<input.length(); i++){
    if(isVowel(input.at(i)) == true){
        vowels++;
    }
}
cout << "Including a, e, i, o, u, and y, that word contains " << vowels << " vowels.\n";
}

Answer 1

您弄错了函数参数的语法，并无意间写了一些合法的东西，但是没有按照您的预期去做。像这样写

bool isVowel(char chara) {
    return chara == 'A' || chara == 'E' || 
        chara == 'I' || chara == 'O' || chara == 'U' || chara == 'Y' || 
        chara == 'a' || chara == 'e' || chara == 'i' || chara == 'o' || 
        chara == 'u' || chara == 'y';
}

使用bool函数制作基本程序以计算元音

1 个答案: