Question

我有一个作业，我必须查看输入的号码是否是阿姆斯特朗号码，问题是当我单击按钮时提示窗口没有显示，只有在我有其余的情况下才会出现的功能写出来。单独显示时，将显示提示窗口。

y -= (jumpCount ** 2) // 2 * neg

Answer 1

您在此字符串上输入了错误（将“ =”更改为“ +”）：

var StrongNum =（firstNum 3）+（secondNum 3）=（thirdNum ** 3）;
您不调用函数
尝试在功能之后添加

armNum（）;

Answer 2

您在tnis行= (firstNum**3) + (secondNum**3) = (thirdNum**3);中使用了'='而不是在'+'和您之间出现了错误

function armNum(){
    var num = prompt("Enter a number between 0 and 999!: ");
    var firstNum;
    var secondNum;
    var thirdNum;
    if(num < 100 && num > 0)
    {
        firstNum = num/10;
        secondNum = num%10;
        var StrongNum = (firstNum**3) + (secondNum**3);
        if( num == StrongNum)
        {
            alert( "nummber " + num + " is an armstrong number!")
        }
    else

        {
            alert( "number" + num + "is not an armstrong number!");        }
    }
    if(num > 99 && num < 1000)
    {
        firstNum = num/100;
        secondNum = (num/10)%10;
        thirdNum = num % 10;
        var StrongNum = (firstNum**3) + (secondNum**3)+(thirdNum**3);
        if( num == StrongNum)
        {
            alert( "nummber " + num + " is an armstrong number!");
        }
        else
        {
            alert("number" + num + "is not an armstrong number!");
        }
    }
}

<body onload=armNum()>
</body>

单击按钮后，提示窗口将不会打开

2 个答案: