我正在寻求简化此代码。有什么办法吗？ Spring MVC + Apex图表
var d = /*[[${s0}]]*/ null`; <-- It is sent via the Spring Framework. Basically represents datetime(in millis) at `d[0]`, `d[3]`,... Temperature at `d[1]`, `d[4]`,... and Humidity at `d[2]`, `d[5]`,...
<script type="text/javascript" th:inline="javascript">
var d = /*[[${s0}]]*/ null;
var options = {
chart: {
type: 'area',
height: 300
},
series: [
{
name: 'Temperature',
data: [
[d[0], d[1]],
[d[3], d[4]],
[d[6], d[7]],
[d[9], d[10]],
[d[12], d[13]],
[d[15], d[16]],
[d[18], d[19]],
[d[21], d[22]],
[d[24], d[25]],
[d[27], d[28]],
[d[30], d[31]],
[d[33], d[34]],
[d[36], d[37]],
[d[39], d[40]],
[d[42], d[43]],
[d[45], d[46]],
[d[48], d[49]],
[d[51], d[52]],
[d[54], d[55]],
[d[57], d[58]],
[d[60], d[61]],
[d[63], d[64]],
[d[66], d[67]],
[d[69], d[70]]
]
},
{
name: "Humidity",
data: [
[d[0], d[2]],
[d[3], d[5]],
[d[6], d[8]],
[d[9], d[11]],
[d[12], d[14]],
[d[15], d[17]],
[d[18], d[20]],
[d[21], d[23]],
[d[24], d[26]],
[d[27], d[29]],
[d[30], d[32]],
[d[33], d[35]],
[d[36], d[38]],
[d[39], d[41]],
[d[42], d[44]],
[d[45], d[47]],
[d[48], d[50]],
[d[51], d[53]],
[d[54], d[56]],
[d[57], d[59]],
[d[60], d[62]],
[d[63], d[65]],
[d[66], d[68]],
[d[69], d[71]]
]
}
],
xaxis: {
type: 'datetime'
},
yaxis: [
{
axisTicks: {
show: true
},
axisBorder: {
show: true,
},
title: {
text: "Temperature"
}
}, {
min: 0,
max: 100,
opposite: true,
axisTicks: {
show: true
},
axisBorder: {
show: true,
},
title: {
text: "Humidity"
}
}
],
legend: {
position: 'top',
horizontalAlign: 'center'
},
tooltip: {
x: {
format: 'HH:mm dd/MM/yy'
},
}
}
var chart = new ApexCharts(document.querySelector("#chart0"), options);
chart.render();
</script>
我只需要简化通过d[0]，d[1]等发送数据的过程。是否有任何循环或其他可用的方法？
答案 0 :(得分：2)
您可以使用一个函数，该函数获取所需元素的数据和模式，并为下一行添加增量。
function mapByPattern(data, pattern, offset) {
var result = [], i = 0;
while (i < data.length) {
result.push(pattern.map(j => data[i + j]));
i += offset;
}
return result;
}
var data = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11],
result = { series: [
{ name: 'Temperature', data: mapByPattern(data, [0, 1], 3) },
{ name: "Humidity", data: mapByPattern(data, [0, 2], 3) }
]};
console.log(result);
答案 1 :(得分：0)
谢谢你，妮娜。代码无法完全按照我的要求工作，但是对修复自己的代码很有帮助。非常感谢！这是一些固定的代码：）
var data = /*[[${s0}]]*/ null;
function mapByPattern(data, pattern, offset) {
var result = [], i = 0;
while (i < data.length) {
result.push(pattern.map(j => data[i + j]));
i += offset;
}
return result;
}
var options = {
chart: {
type: 'area',
height: 300
},
series: [
{
name: 'Temperature',
data: mapByPattern(data, [0, 1], 3)
},
{
name: "Humidity",
data: mapByPattern(data, [0, 2], 3)
}
],
xaxis: {
type: 'datetime'
},
yaxis: [
{
axisTicks: {
show: true
},
axisBorder: {
show: true,
},
title: {
text: "Temperature"
}
}, {
min: 0,
max: 100,
opposite: true,
axisTicks: {
show: true
},
axisBorder: {
show: true,
},
title: {
text: "Humidity"
}
}
],
legend: {
position: 'top',
horizontalAlign: 'center'
},
tooltip: {
x: {
format: 'HH:mm dd/MM/yy'
},
}
}
var chart = new ApexCharts(document.querySelector("#chart0"), options);
chart.render();
答案 2 :(得分：-2)
尝试这样（删除重复和无关的代码）
vertex.color = adjustcolor(colorvector,alpha)