Question

我正在创建一个Android应用，用于控制使用RPI的调酒师的配置

我想在列表视图中显示所有当前的饮料及其成分。

这是我从服务器获得的Json响应：

    [  
{  
    "name":"Rum & Coke",
    "ingredients":{  
        "rum":50,
        "coke":150
    }
},
{  
    "name":"Gin & Tonic",
    "ingredients":{  
        "tonic":10,
        "gin":10
    }
},
{  
    "name":"Long Island",
    "ingredients":{  
        "tequila":15,
        "oj":30,
        "rum":15,
        "vodka":15,
        "coke":100,
        "gin":15
    }
},
{  
    "name":"Screwdriver",
    "ingredients":{  
        "vodka":50,
        "oj":150
    }
},
{  
    "name":"Margarita",
    "ingredients":{  
        "mmix":150,
        "tequila":50
    }
},
{  
    "name":"Gin & Juice",
    "ingredients":{  
        "oj":150,
        "gin":50
    }
},
{  
    "name":"Tequila Sunrise",
    "ingredients":{  
        "tequila":50,
        "oj":150
    }
}
]

这是Drink.class

public class Drink {
    @SerializedName("name")
    private String name;
    @SerializedName("ingredients")
    private Map<String, Integer> ingredients;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Map<String, Integer> getIngredients() {
        return ingredients;
    }

    public void setIngredients(Map<String, Integer> ingredients) {
        this.ingredients = ingredients;
    }
}

现在，我可以在列表视图中显示饮料名称，并且仅在地图的第二值上显示此for语句

Drink d = drinksArrayList.get(position);
        System.out.println(d.getIngredients().size());
        for (Map.Entry<String, Integer> ingredient : d.getIngredients().entrySet()) {
            holder.ingredient0.setText(ingredient.getKey());
            holder.ingredient1.setText(Integer.toString(ingredient.getValue()));
        }

如果使用朗姆酒和焦炭，则此for语句将焦炭150打印到屏幕上。

有人知道如何正确序列化此Json并将其打印到列表视图吗？

Answer 1

看起来json已正确反序列化，但是您使用了错误的字段来填充TextViews。您应该使用getName作为名称，即“朗姆酒和可乐”，然后将地图连接起来以获取成分列表。

我认为您想做这样的事情：

Drink d = drinksArrayList.get(position);
holder.ingredient0.setText(d.getName()));
StringBuilder ingredients = new StringBuilder();
for (Map.Entry<String, Integer> ingredient : d.getIngredients().entrySet()) {
    ingredients.append(" ");
    ingredients.append(ingredient.getKey());
    ingredients.append(", ");
    ingredients.append(Integer.toString(ingredient.getValue()));
    ingredients.append("\n");
}
holder.ingredient1.setText(ingredients.toString().trim());

如何从映射到TextView获取两个键/值对

1 个答案: