Question

我今天早些时候制作了一个AppleScript，用于显示YouTube for Geektools的订阅者人数，但我希望它可以简化人们的使用，并尝试使其脱离文件名（例如，使用subcount-PewDiePie .scpt并输出PewDiePie的子计数），然后我从文件名中输入名称就起作用了，但是当我尝试从api的响应中取出数字时，这给了我错误

工作（原始）代码

set apiResponse to (do shell script "curl -s 'https://www.googleapis.com/youtube/v3/channels?part=statistics&forUsername=PewDiePie&fields=items%2Fstatistics%2FsubscriberCount&key=AIzaSyAEQGj2ZcDrTU0ZqzteD8eDVJwB9cpmvEo'")

on returnNumbersInString(inputString)
    set s to quoted form of inputString
    do shell script "sed s/[a-zA-Z\\']//g <<< " & s
    set dx to the result
    set numlist to {}
    repeat with i from 1 to count of words in dx
        set this_item to word i of dx
        try
            set this_item to this_item as number
            set the end of numlist to this_item
        end try
    end repeat
end returnNumbersInString

returnNumbersInString(apiResponse)

破碎的可定制代码

set channelName to path to me as text
set oldDelims to AppleScript's text item delimiters
set AppleScript's text item delimiters to {"subcount-"}
set nameFilter to text items of channelName
set channelName to item 2 of nameFilter

set AppleScript's text item delimiters to {"."}
set nameFilter to the text items of channelName
set channelName to item 1 of nameFilter

set curlLink to "https://www.googleapis.com/youtube/v3/channels?part=statistics&forUsername=" & channelName & "&fields=items%2Fstatistics%2FsubscriberCount&key=AIzaSyAEQGj2ZcDrTU0ZqzteD8eDVJwB9cpmvEo"
set curlCommand to "curl -s " & (quoted form of curlLink)

set apiResponse to {do shell script curlCommand}
on returnNumbersInString(inputString)
    set s to quoted form of inputString
    do shell script "sed s/[a-zA-Z\\']//g <<< " & s
    set dx to the result
    set numlist to {}
    repeat with i from 1 to count of words in dx
        set this_item to word i of dx
        try
            set this_item to this_item as number
            set the end of numlist to this_item
        end try
    end repeat
end returnNumbersInString

returnNumbersInString(apiResponse)

每次我做第二个它都会输出错误

Can’t get quoted form of {"{
 \"items\": [
  {
   \"statistics\": {
    \"subscriberCount\": \"76957805\"
   }
  }
 ]
}"}.

从网站获取信息后立即失败，这没有任何意义，因为除了如何获得网站链接之外，没有任何代码已被更改，任何人都可以帮我解决这个问题

Answer 1

您已将do shell script命令用大括号括起来：

set apiResponse to {do shell script curlCommand}

因此，apiResponse现在是一个包含JSON字符串而不只是一个JSON字符串的列表。删除括号，使该行显示为：

set apiResponse to do shell script curlCommand

AppleScript无法获得引号形式的api响应

1 个答案: