Question

每当我运行此代码时，它都会在screen.blit之前停止，同时仍在循环，并一遍又一遍地打印'debug3'。

它甚至都没有意识到未定义屏幕，我的意图是让它运行screen.blit。

...
playermove = 5
walkL=pygame.image.load("files/sprites/walkL.png")
walkR=pygame.image.load("files/sprites/walkR.png")
currentSprite = walkL

#single sprite size (width, height)
h=128
w=57   
numImages = 4
    #counter
cImage=0


class Player:

    def animation(self):    
        global cImage,numImages,currentSprite,playerRect,w,h        
        if (cImage>=numImages-1):
            cImage=0
        else:
            cImage+=1
        print('debug3')

        screen.blit(currentSprite,playerRect, (cImage*w,0,w,h))

while True:
    player.animation()

Answer 1

如果您查看else语句，则需要缩进'print'调用以与'cImage + = 1'对齐。

----来自代码示例的片段----

$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
curl_setopt($ch, CURLOPT_ENCODING , "gzip");
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'Accept-Encoding: gzip, deflate, br',
));
$html = curl_exec($ch);
curl_close($ch);

-------结束代码段-----------------

While循环在if语句处停止-pygame

1 个答案: