Question

使用pytumblr客户端，我得到这种类型的输出

{
"total_blogs": 2,
"blogs": [
  {
    "name": "testblog",
    "title": "testblog",
    "description": "A testblog",
    "url": "https://testblog.tumblr.com/",
    "uuid": "t:g8wqt6wBUe3AJkJXYHn1",
    "updated": 1526680515 
  },
  {
    "name": "testblog1",
    "title": "testblog1",
    "description": "A testblog1",
    "url": "https://testblog1.tumblr.com/",
    "uuid": "t:qwuedBBFIPMTViKhjozp",
    "updated": 1510382395 
  }],
"_links": {
  "next": {
    "href": "/v2/user/following?offset=20",
    "method": "GET",
    "query_params": {
      "offset": "20"
    }
  }
}

} }

我可以很好地打印total_blogs和blog的值，但是我无法访问行程值，特别是url，我无法应用教程或我见过的其他一些示例可以帮助解决此问题。

结束游戏基本上只是为了能够循环播放程序，直到我获得所有url值为止。我一次只能访问20个博客，这就是我将必须获得的url值

Accessing json array in python without referring to its name

此页面中的答案似乎是解决方案，但尝试将其应用于我的代码

for anything in usrFollowing:
  if isinstance(usrFollowing[anything], list):
    for values in usrFollowing[anything]:
      print(values['blogs']['name'])

只是给我KeyError：从最后一行开始'博客'。我不确定目前还可以做什么

我遇到的另一个问题是弄清楚如何将代码输出为更具可读性的格式。在tumblr网站控制台上，它的输出类似于上面显示的初始代码，但是我得到的只是在控制台上进行的连续打印。有什么办法可以改变这个吗？

Answer 1

这应该检索您的tumblr遵循的博客URL：

import pytumblr
client = pytumblr.TumblrRestClient(...)  # replace ... with your credentials

usrFollowing = client.following()
for blog in usrFollowing['blogs']:
    print(blog['url'])

我认为理解这种结构的方式是一次。

usrFollowing var是字典

...
usrFollowing = client.following()
for key in usrFollowing.keys():
    print(key)

# outputs:
#   blogs
#   _links
#   total_blogs

因此，要访问每个博客，我们可以使用键blogs遍历它们：

...
usrFollowing = client.following()
for blog in usrFollowing['blogs']:
    print(blog)
# outputs something like:
#   {u'updated': 1539793245, u'uuid': u't:CwoihvyyOxn8Mk5TUS0KDg', u'title': u'Tumblr Engineering', u'url': u'https://engineering.tumblr.com/', u'name': u'engineering', u'description': u'Dispatches from the intrepid tinkerers behind technology at Tumblr.'}
#   {u'updated': 1545058816, u'uuid': u't:0aY0xL2Fi1OFJg4YxpmegQ', u'title': u'Tumblr Staff', u'url': u'https://staff.tumblr.com/', u'name': u'staff', u'description': u''}

有几种方法可以以更“人类”的格式输出对象，使用pprint或将对象转换为JSON并指定缩进量：

...

import pprint
import json

print('Python pretty-printed')
for blog in usrFollowing['blogs']:
    pprint.pprint(blog)

print('')

print('JSON pretty-printed')
for blog in usrFollowing['blogs']:
    print(json.dumps(blog, indent=2))
# outputs something like:
#   Python pretty-printed
#   {u'description': u'Dispatches from the intrepid tinkerers behind technology at Tumblr.',
#    u'name': u'engineering',
#    u'title': u'Tumblr Engineering',
#    u'updated': 1539793245,
#    u'url': u'https://engineering.tumblr.com/',
#    u'uuid': u't:CwoihvyyOxn8Mk5TUS0KDg'}
#   {u'description': u'',
#    u'name': u'staff',
#    u'title': u'Tumblr Staff',
#    u'updated': 1545058816,
#    u'url': u'https://staff.tumblr.com/',
#    u'uuid': u't:0aY0xL2Fi1OFJg4YxpmegQ'}
#   
#   JSON pretty-printed
#   {
#     "updated": 1539793245,
#     "uuid": "t:CwoihvyyOxn8Mk5TUS0KDg",
#     "title": "Tumblr Engineering",
#     "url": "https://engineering.tumblr.com/",
#     "name": "engineering",
#     "description": "Dispatches from the intrepid tinkerers behind technology at Tumblr."
#   }
#   {
#     "updated": 1545058816,
#     "uuid": "t:0aY0xL2Fi1OFJg4YxpmegQ",
#     "title": "Tumblr Staff",
#     "url": "https://staff.tumblr.com/",
#     "name": "staff",
#     "description": ""
#   }

这些词典有一个url键，因此您可以使用以下命令进行打印：

...
usrFollowing = client.following()
for blog in usrFollowing['blogs']:
    print(blog['url'])
# outputs something like:
#   https://engineering.tumblr.com/
#   https://staff.tumblr.com/

对如何访问json代码中的嵌套值感到困惑？

1 个答案: