Question

所以可以说我有3行代码

ABC
123
!@#

我如何创建for循环以输出将它们组合在一起的方式数量？

E ABC123!@#, ABC!@#123, 123ABC!@#$

这是我当前的代码行

 #!/bin/bash



    alphabet='ABC' numbers='123' special='!@#'

 for name in $alphabet$numbers$special 
  do   
  echo $name 
  done  
  echo  done

Answer 1

alphabet='ABC' numbers='123' special='!@#'

for name1 in $alphabet $numbers $special 
#on 1st iteration, name1's value will be ABC, 2nd 123 ...
do
    for name2 in $alphabet $numbers $special
    do
        for name3 in $alphabet $numbers $special
        do
            #here we ensure that we want strings only as combination of that three strings 
            if [ $name1 != $name2 -a $name2 != $name3 ]
            then
            echo $name1$name2$name3
            fi
        done
    done
done

如果您还希望打印字符串，例如 123123123 和 ABCABCABC ，请在有条件的情况下删除

Answer 2

您还可以使用括号扩展完全没有循环地执行此操作（但是您会失去排除功能，例如ABCABCABC）。例如：

#!/bin/bash

alpha='ABC'
num='123'
spec='!@#'

printf "%s\n" {$alpha,$num,$spec}{$alpha,$num,$spec}{$alpha,$num,$spec}

使用/输出示例

$ bash permute_brace_exp.sh
ABCABCABC
ABCABC123
ABCABC!@#
ABC123ABC
ABC123123
ABC123!@#
ABC!@#ABC
ABC!@#123
ABC!@#!@#
123ABCABC
123ABC123
123ABC!@#
123123ABC
123123123
123123!@#
123!@#ABC
123!@#123
123!@#!@#
!@#ABCABC
!@#ABC123
!@#ABC!@#
!@#123ABC
!@#123123
!@#123!@#
!@#!@#ABC
!@#!@#123
!@#!@#!@#

为3个不同的变量创建一个循环以输出所有可能的组合

2 个答案: