Question

dictionary = {'Name':['Sam','Rafael','Albert','Prapul','Zorg','Peter','Sandy','Kristena','Noah','William','Alexander'],
              'Number':[9842657266,2548759249,5859715540,9874515875,8974511147,9874447574,5987415877,8898874714,9985852124,
                        8015005998,9633215749],
              'Email':['sam@gmail.com','raf@outlook.com','albert12@gmail.com','prapul@yahoo.com','zorg124@hotmail.com',
                       'pete345@yahoo.com','sandy007@outlook.com','kristena789@hotmail.com','noah123do@gmail.com',
                       'william12sam@gmail.com','alex65tgp@hotmail.com']}


 search = input('Please enter the name you would like to search:')
        if search in dictionary.keys():
            #print user details
        else:
            print ('User Not Found')

我需要在词典中搜索特定用户并打印用户名电话号码和电子邮件地址

Answer 1

您可以在字典中搜索特定用户，并通过以下方式打印用户名电话号码和电子邮件地址：

dictionary = {'Name': ['Sam','Rafael','Albert','Prapul','Zorg','Peter','Sandy','Kristena','Noah','William','Alexander'],
              'Number':[9842657266,2548759249,5859715540,9874515875,8974511147,9874447574,5987415877,8898874714,9985852124,
                    8015005998,9633215749],
              'Email':['sam@gmail.com','raf@outlook.com','albert12@gmail.com','prapul@yahoo.com','zorg124@hotmail.com',
                   'pete345@yahoo.com','sandy007@outlook.com','kristena789@hotmail.com','noah123do@gmail.com',
                   'william12sam@gmail.com','alex65tgp@hotmail.com']}

search = input('Please enter the name you would like to search:\n')
index = -1
for i in range(len(dictionary['Name'])):
    if dictionary['Name'][i] == search:
        index = i

if index >= 0:
    print('Phone number:', dictionary['Number'][index])
    print('Email:', dictionary['Email'][index])
else:
    print('User Not Found')

结果

>>> Please enter the name you would like to search:
>>> Albert
>>> Phone number: 5859715540
>>> Email: albert12@gmail.com

Answer 2

类似的功能

代码：

def find_name(name_to_find):
    return next((x for x in zip(*(
        dictionary[key] for key in ('Name', 'Number', 'Email')))
                 if x[0] == name_to_find), None)

会做到这一点。

测试代码：

dictionary = {'Name':['Sam','Rafael','Albert','Prapul','Zorg','Peter','Sandy','Kristena','Noah','William','Alexander'],
              'Number':[9842657266,2548759249,5859715540,9874515875,8974511147,9874447574,5987415877,8898874714,9985852124,
                        8015005998,9633215749],
              'Email':['sam@gmail.com','raf@outlook.com','albert12@gmail.com','prapul@yahoo.com','zorg124@hotmail.com',
                       'pete345@yahoo.com','sandy007@outlook.com','kristena789@hotmail.com','noah123do@gmail.com',
                       'william12sam@gmail.com','alex65tgp@hotmail.com']}

print(find_name('Zorg'))
print(find_name('Junk'))

结果：

('Zorg', 8974511147, 'zorg124@hotmail.com')
None

Answer 3

您的问题已解决，但我有另一种逻辑：

dictionary = {'Sam':[9842657266,'sam@gmail.com'],'alex':[2548759249,'william12sam@gmail.com']}

search = input('Please enter the name you would like to search : ')

if search in dictionary.keys():
    #here your condition
    print('Phone Number :-> ' , dictionary[search][0] ) #index 0 is Phone number
    print('Email :-> ' , dictionary[search][1]) #index 1 is email
else :
    print('User Not Found')

Answer 4

在Stephen代码中几乎没有修改：

def search(keyword):
    for x in zip(*(dictionary[key] for key in (dictionary.keys()))):
        if x[0] == keyword:
            return x[1],x[2]

python搜索字典值并打印

4 个答案:

结果

代码：

测试代码：

结果：