Question

我有一个包含以下内容的分块列表：

ChunkedList = ['2018-12-14 15:00:00', 'A : aa1', 'B: bb2', 'C: cc3'] ['2018-12-14 16:00:00', 'A : aa2', 'B: bb2','C: cc1']['2018-12-14 17:00:00', 'A : aa3', 'B: bb1','C: cc3']['2018-12-14 18:00:00', 'A : aa3', 'B: bb1','C: cc3']['2018-12-14 19:00:00', 'A : aa3', 'B: bb1','C: cc3']['2018-12-14 20:00:00', 'A : aa3', 'B: bb1','C: cc3']

如果在未分类的列表上运行以下代码，则会得到包含相关时间的单行。

import datetime
hours = [(datetime.time(i).strftime('%H:%M:%S')) for i in range(6,18)]
WFList = [line for line in FullList if any(hour in line for hour in hours)]

赞：

WFList= ['2018-12-14 15:00:00','2018-12-14 16:00:00','2018-12-14 17:00:00']

我当前对分块列表的代码是：

for chunk in ChunkedList:
    if any(hour in chunk for hour in hours):
        print(chunk)

它什么也不返回。我想返回一个列表，其中包含以下范围内的时间：

IdealList = ['2018-12-14 15:00:00', 'A : aa1', 'B: bb2', 'C: cc3'] ['2018-12-14 16:00:00', 'A : aa2', 'B: bb2','C: cc1']['2018-12-14 17:00:00', 'A : aa3', 'B: bb1','C: cc3']

我通读了很多关于迭代和分块列表的文章，并感到困惑。任何和所有帮助表示赞赏！谢谢。

Answer 1

我相信问题在于hours严格包含时间。虽然您的列表同时包含date和time。您需要对字符串使用split方法来解析列表。试试这个：

import datetime

hours = [(datetime.time(i).strftime('%H:%M:%S')) for i in range(6,18)]

ChunkedList = [['2018-12-14 15:00:00', 'A : aa1', 'B: bb2', 'C: cc3'],
               ['2018-12-14 16:00:00', 'A : aa2', 'B: bb2','C: cc1'],
               ['2018-12-14 17:00:00', 'A : aa3', 'B: bb1','C: cc3'],
               ['2018-12-14 18:00:00', 'A : aa3', 'B: bb1','C: cc3'],
               ['2018-12-14 19:00:00', 'A : aa3', 'B: bb1','C: cc3'],
               ['2018-12-14 20:00:00', 'A : aa3', 'B: bb1','C: cc3']]

result = [big_list for big_list in ChunkedList if big_list[0].split()[1] in hours]
# [['2018-12-14 15:00:00', 'A : aa1', 'B: bb2', 'C: cc3'], ['2018-12-14 16:00:00', 'A : aa2', 'B: bb2', 'C: cc1'], ['2018-12-14 17:00:00', 'A : aa3', 'B: bb1', 'C: cc3']]

big_list[0].split()[1]仅在查看时查看其是否在hours中提供的范围内。

遍历一个分成大块的列表

1 个答案: