令人困惑的标题，但我想知道的是如何弄乱长行的单词，或者在这种情况下为数字。
我正在记下用户键入的城镇的邮政编码。某些城镇的邮政编码很多，并且输出很长。
我想将这些行每100个字符分解一遍，以便于阅读。
I would like output to look like this:
You asked me to search for place: Chicago, Il
Chicago, Il has zip codes: [60601, 60602, 60603, 60604, 60605, 60606,
60607, 60608, 60609, 60610, 60611, 60612, 60613, 60614, 60615, 60616,
60617, 60618, 60619, 60620, 60621, 60622, 60623, 60624, 60625, 60626,
60628, 60629, 60630, 60631, 60632, 60633, 60634, 60636, 60637, 60638,
60639, 60640, 60641, 60643, 60644, 60645, 60646, 60647, 60649, 60651,
60652, 60653, 60654, 60655, 60656, 60657, 60659, 60660, 60661, 60663,
60664, 60665, 60667, 60668, 60669, 60670, 60671, 60672, 60673, 60674,
60675, 60677, 60678, 60679, 60680, 60681, 60683, 60684, 60685, 60687,
60690, 60691, 60693, 60694, 60697, 60699, 60701]
^^^ My current output is that, but all in one line. ^^^
我想知道如何解决它，使它看起来像这样。这是我目前的代码。
import java.util.ArrayList;
import java.io.*;
import java.util.*;
/**
* In this class, I will obtain two private variables that are a type
String and ArrayList.
* The String will be the location that the user types in and the zip
code will be the zip codes
* that exist within that town/city.
*/
public class Place
{
private ArrayList<String> zipCodes;
private String location;
/**
* In this method, we find the file in which we will retrieve this
data. We put it in a Scanner and
* put each line in an ArrayList that is ZipCodes.
* @throws FileNotFoundException if the file doesn't exist.
*/
public Place() throws FileNotFoundException
{
File zipsFile = new File("/Users/adanvivero/IdeaProjects/assignment
6/zips.txt");
zipCodes = new ArrayList<String>();
Scanner coordinates = new Scanner(zipsFile);
while(coordinates.hasNextLine())
{
String lineScan = coordinates.nextLine();
zipCodes.add(lineScan);
}
}
/**
* In this method, we print out the zip code of the town/city in which
the user typed in.
* @throws FileNotFoundException We use this since we used a file in
the String method, setZipCode
* down below.
*/
public void addPlace() throws FileNotFoundException
{
String theSummary = location + " has zip codes: " + setZipCodes();
if(theSummary.length() > 100)
{
System.out.println();
System.out.print(theSummary);
}
}
/**
* In this method, we retrieve the zip code of the city/town. I have
two ArrayList since I don't need
* to get the coordinates of the file, but rather only the name of the
town and the zip code of it. Therefore,
* I add the zip codes into one of the ArrayList, which in this
instance happen to be our private one, and
* the name of the location in another Arraylist.
* @return We return a String that will be the zipCodes which is in an
Array, but converted as a String.
* @throws FileNotFoundException We retrieve the file in which these
will come out in. If the file doesn't exist,
* we throw a FileNotFoundException.
*/
public String setZipCodes() throws FileNotFoundException
{
File zipsFile = new File("/Users/adanvivero/IdeaProjects/assignment
6/zips.txt");
//ArrayList<String> zips = new ArrayList<String>();
zipCodes = new ArrayList<String>();
ArrayList<String> codes = new ArrayList<String>();
Scanner console = new Scanner(zipsFile);
while(console.hasNextLine())
{
String z = console.nextLine();
String [] zip = z.split("\t");
String [] code = z.split("\t");
if(location.equalsIgnoreCase(code[3]))
{
zipCodes.add(zip[0]);
codes.add(code[3]);
}
}
String theSummary = zipCodes.toString();
for(int i = 0; i <= theSummary.length()-1; i++)
{
while(theSummary.charAt(i) == 100)
{
System.out.println();
}
}
return zipCodes.toString();
}
/**
* In this String method, we as the user to type in a place and we
return the place the user typed in so other
* methods can use it.
* @return it returns the String of the location the user types in.
*/
public String getLocation()
{
Scanner wuddup = new Scanner(System.in);
System.out.print("You asked me to search for place: ");
location = wuddup.nextLine();
return location;
}
}
因此，我相信要解决我的问题是在setZipCode（）方法下或在我的addPlace（）方法上。
答案 0 :(得分：2)
在addPlace（）中执行以下操作：
String theSummary = location + " has zip codes: " + setZipCodes();
String theNewSummary = "";
for(int i = 0; i < theSummary.length()-1; i = i+100){
if(i+99 < theSummary.length()-1)
theNewSummary += theSummary.substring(i, i+99)+"\r\n";
else
theNewSummary += theSummary.substring(i, theSummary.length()-1);
}
System.out.print(theNewSummary );
为了每行显示10个邮政编码：
String theSummary = location + " has zip codes: \r\n";
String[] zipCodes = setZipCodes().split(" ");
for(int i = 0; i < zipCodes.length; i++){
theSummary += " "+zipCodes[i];
if(i%10 == 0 && i !=0)
theSummary +="\r\n"
}
System.out.print(theSummary );
答案 1 :(得分：0)
从addPlace（）中，您可以调用此方法来格式化输出。
此方法的优点是它可以：-
工作代码：-
/**
* Format a String to specific line length.
* @param summary : Input string
* @param maxLineLength Max line length.
* @param delim String delimeter to be used for breaking the string like space or comma
* @return the formated sting
*/
public static String formatSummary(String summary, int maxLineLength, String delim) {
//convert long string to array of word by delim and discard empty string.
List<String> summarySplitByDelim = Arrays.stream(summary.split(delim)).filter(a->a.length() > 0)
.collect(Collectors.toList());
String newLine = System.getProperty("line.separator");
StringBuilder formattedSummary = new StringBuilder();
StringBuilder currentLine = new StringBuilder();
for (String currentWord : summarySplitByDelim) {
// Keep on adding word by word to currentline
currentLine.append(currentWord.trim()).append(delim);
//if current line execeed our line length, dump everything to formatedSummary and reset currentline
if(currentLine.length() > maxLineLength){
formattedSummary.append(currentLine).append(newLine);
currentLine = new StringBuilder();
}
}
//Add the last line if not added because the loop exited.
if(currentLine.length() > 0){
formattedSummary.append(currentLine).append(newLine);
}
return formattedSummary.toString();
}
调用类似formatSummary(data, 80, " ");的方法将产生输出
Chicago, Il has zip codes: [60601, 60602, 60603, 60604, 60605, 60606, 60607, 60608,
60609, 60610, 60611, 60612, 60613, 60614, 60615, 60616, 60617, 60618, 60619, 60620,
60621, 60622, 60623, 60624, 60625, 60626, 60628, 60629, 60630, 60631, 60632, 60633,
60634, 60636, 60637, 60638, 60639, 60640, 60641, 60643, 60644, 60645, 60646, 60647,
60649, 60651, 60652, 60653, 60654, 60655, 60656, 60657, 60659, 60660, 60661, 60663,
60664, 60665, 60667, 60668, 60669, 60670, 60671, 60672, 60673, 60674, 60675, 60677,
60678, 60679, 60680, 60681, 60683, 60684, 60685, 60687, 60690, 60691, 60693, 60694,
60697, 60699, 60701]