这是一个非常基本的问题,但是以某种方式我的循环无法正常工作。我有一个两列的pandas数据框;路径和单词。一个神经网络以词来预测结果值,但是它仍然是整数。我编写了一个for循环,用单词替换了这些整数,但是df中没有任何变化。我的df:
path word
0 f7f172c01bec6a3e9a36dcafdf9e02e7df3522e4.wav 21
1 c17c29e392c57a9243ed52175568b40c04912194.wav 21
2 eea9239d4986b1f7dbffdcce76e0fce6e5f38ca8.wav 21
3 4fec4b033ba19d1ac875c0c062fda2869dbece73.wav 21
我的循环:
for i in df['word']:
if i == 0:
i == "backward"
elif i == 1:
i == "bed"
elif i == 2:
i == "bird"
elif i == 3:
i == "cat"
elif i == 4:
i == "dog"
elif i == 5:
i == "down"
elif i == 6:
i == "eight"
elif i == 7:
i == "five"
elif i == 8:
i == "follow"
elif i == 9:
i == "forward"
elif i == 10:
i == "four"
elif i == 11:
i == "go"
elif i == 12:
i == "happy"
elif i == 13:
i == "house"
elif i == 14:
i == "learn"
elif i == 15:
i == "left"
elif i == 16:
i == "marvin"
elif i == 17:
i == "nine"
elif i == 18:
i == "no"
elif i == 19:
i == "off"
elif i == 20:
i == "on"
elif i == 21:
i == "one"
elif i == 22:
i == "right"
elif i == 23:
i == "seven"
elif i == 24:
i == "sheilla"
elif i == 25:
i == "six"
elif i == 26:
i == "stop"
elif i == 27:
i == "three"
elif i == 28:
i == "tree"
elif i == 29:
i == "two"
elif i == 30:
i == "up"
elif i == 31:
i == "visual"
elif i == 32:
i == "wow"
elif i == 33:
i == "yes"
elif i == 34:
i == "zero"
答案 0 :(得分:2)
您可以使用pd.Series.map
:
#Add the rest of your mapping here (I just included a few)
mapping = {0: 'backward', 1: 'bed', 21: 'one', 22: 'right'}
df['word'] = df['word'].map(mapping)
返回:
path word
0 f7f172c01bec6a3e9a36dcafdf9e02e7df3522e4.wav one
1 c17c29e392c57a9243ed52175568b40c04912194.wav one
2 eea9239d4986b1f7dbffdcce76e0fce6e5f38ca8.wav one
3 4fec4b033ba19d1ac875c0c062fda2869dbece73.wav one