Question

   1.   Product A   7.5
   2.   Product A   7.3
   3.   Product A   7.4
   4.   Product B   6.2
   5.   Product B   6.5
   6.   Product B   6.01
   7.   Product c   2.4
   8.   Product c   2.0

不包括产品A的最大值行= 7.5，则该产品A的剩余计数将为2。所以我需要这样的

Product A  2
Product B  2
Product C  1..

Answer 1

如果最大值没有重复，则只需从COUNT中减去1：

SELECT product, COUNT(*) - 1 AS counter FROM products GROUP BY product;

，如果有重复项并且您希望将它们全部排除，则此操作：

SELECT p.product, COUNT(*) AS counter 
FROM products p 
WHERE p.value < (SELECT MAX(value) FROM products WHERE product = p.product) 
GROUP BY p.product;

或者如果您想返回零：

SELECT 
  p.product, 
  COUNT(*) - (
    SELECT COUNT(*) 
    FROM products 
    WHERE 
      product = p.product 
      AND 
      value = (
        SELECT MAX(value) FROM products WHERE product = p.product
      )
  ) AS counter 
FROM products p 
GROUP BY p.product;

Answer 2

您可能重复了相同的最大值。如果是这样：

select t.product
from t join
     (select product, max(price) as maxprice
      from t
      group by product
     ) tt
     on t.product = tt.product
where t.price < t.maxprice
group by t.product;

获取产品数量（不包括该产品在sql中的最大值）

2 个答案: