I've been trying to make a generic method so that I'm able to parse in any URL and Classes; They have been successful but for now I'd like to gather data from the text; instead of the title. Etc: "Xiaomi 70Mai Pro"
I've tried referencing from these two sources; but I'm still unsure...
Parse HTML Table for URL, Place into List
links = 'SampleLink... with table cell'
def getURLData(url): # scrap data from Link
try:
page = requests.get(url)
content = page.content
soup = BeautifulSoup(content, "html.parser")
return soup
except Exception as e:
print('Error.getURLData:', e)
return None
inputLink = getURLData(links)
def tableCheck(): # if there's a table cell;
data = []
for table_tag in inputLink.find_all('td', {'class': 'row1'}):
topic_title = table_tag.find('a', href=True)
if topic_title:
datum = {'topic_title': topic_title['title']}
data.append(datum)
return data
print(tableCheck())
这是输出
{'topic_title': 'This topic was started: Dec 6 2018, 12:20 PM'},
{'topic_title': 'This topic was started: Nov 19 2018, 10:30 AM'},
{'topic_title': 'This topic was started: Nov 28 2018, 09:16 PM'},
{'topic_title': 'This topic was started: Oct 3 2018, 11:10 AM'},
这是我要从中提取数据的单元格;我曾尝试使用topic_title = table_tag.find('a', href=True).text
,但我真的怀疑是否行得通;我对BeautifulSoup仍然不太了解,我一直在思考如何获取数据。我可以尝试另一个for循环吗?提取其中的数据?
<td class = "row1" valign = "middle" >
<div >
<div style = "float:left" >
<a href = "/topic/4667583" title = "This topic was started: Oct 3 2018,
11:10 AM" >
Xiaomi 70Mai Pro < /a >
</div >
<br >
</div >
</td
答案 0 :(得分:1)
要添加到现有答案中,您唯一需要做的修改就是将链接文本添加到词典中:
tensor1 = output_of_a_layer_or_input1
tensor2 = output_of_a_layer_or_input2
divResult = Lambda(lambda x: x[0]/x[1])([tensor1,tensor2])