Question

以下功能未获得正确的结果：

function getMentions($content) {
    global $db;
    $mention_regex = "/@+([a-zA-Z0-9-_]+)/"; //mention regrex to get all @texts
    $regexIt = preg_match_all($mention_regex, $content, $matches);
    if ($regexIt) { 
         foreach ($matches[1] as $key => $match) {
             if ($key === 0) continue;
                 $mentioned[] = mysqli_real_escape_string($db, $match[0]);
                 $match_user = mysqli_query($db, "SELECT user_id, user_name FROM dot_users WHERE user_name  IN ('" . implode("','", $matches[1]) . "')") or die(mysqli_error($db)); 
                 $userDeti = mysqli_fetch_array($match_user, MYSQLI_ASSOC);
                 echo $userDeti['user_id'];
                 echo $userDeti['user_name'];
                 $match_search = '@' . $match . '';  
                 $match_replace = '<a target="_blank" href="' . $userDeti['user_name'] . '">@' . $userDeti['user_name'] . '</a>'; 
                 if (isset($userDeti['user_name'])) {
                        $content = str_replace($match_search, $match_replace, $content);
                   }
            }
    }
    return $content;
}

例如，我想在屏幕上打印user_name和user_id，但不打印。

echo $userDeti['user_id']; // echo is empty
echo $userDeti['user_name'];  //echo is empty output

您能告诉我我做错了还是不完整的事情？

Answer 1

我未经测试的建议...

module.exports = {
    mode    : 'production',
    // Don't attempt to continue if there are any errors.
    bail    : true,
 
    devtool : shouldUseSourceMap ? 'source-map' : false,
    // In production, we only want to load the app code.
    entry   : [paths.appIndexJs],
    output  : {
    // The build folder.
        path                          : paths.appBuild,
        
        filename                      : 'static/js/[name].[chunkhash:8].js',
        chunkFilename                 : 'static/js/[name].[chunkhash:8].chunk.js',
     
        publicPath                    : publicPath,
      
        devtoolModuleFilenameTemplate : info =>
            path
                .relative(paths.appSrc, info.absoluteResourcePath)
                .replace(/\\/g, '/')
    },
    ...}

可能有错别字，但总的思路就在那里。捕获提及内容并尝试避免发送电子邮件，查找ID，替换所有提及内容。

@mention系统无法产生正确的输出

1 个答案: