Question

我有两个表：tableA和tableB

表A

------------------------------
|      CD      |   stg_cd    |
------------------------------
|    APDN_82   |   CUSC      |
|    APDN_82   |   CUC       |
------------------------------

表B

------------------------------
|     stg_cd   |   srt_ordr  |
------------------------------
|    CUSC      |     1       |
|    KLD       |     3       |
|    CUC       |     2       |
------------------------------

我正在尝试使用表A中的当前数据（即CUSC）选择表B中数据的下一个顺序（即CUC）

我的预期结果应该是

------------------------------
|     CD       |   stg_cd    |
------------------------------
|    APDN_82   |     CUC     |
------------------------------

这是我尝试过的

 (SELECT * FROM tableA AS A
            WHERE A.ID = 'APDN_82' AND A.stg_cd 
        IN (SELECT lead('CUSC') over (order by B.srt_ordr) from tableB AS B)

但是在这里我得到一个错误：'lead'不是公认的内置函数名称。我试图将兼容性级别更改为110，但是我没有更改它的权限。还有其他不用铅的方法吗？

Answer 1

这将起作用：

select n.* from tableA n,(select * from tableB  where srt_ordr=(select srt_ordr from 
tableB where stg_cd='CUSC')+1)m  
where 
n.stg_cd=m.stg_cd

Answer 2

您可能需要按tablea.CD进行分区，并找到每个分区的下一行。您可以为此使用ROW_NUMBER()：

SELECT *
FROM (
    SELECT tablea.*, ROW_NUMBER() OVER (PARTITION BY tablea.CD ORDER BY tableb.srt_ordr) AS rn
    FROM tablea
    INNER JOIN tableb ON tablea.stg_cd = tableb.stg_cd
    WHERE tableb.srt_ordr > (SELECT srt_ordr FROM tableb WHERE stg_cd = 'CUSC')
)
AS x
WHERE rn = 1

Demo on DB<>Fiddle

或者您可以使用相关子查询：

SELECT *
FROM tablea
WHERE stg_cd = (
    SELECT TOP 1 stg_cd
    FROM tableb
    WHERE stg_cd IN (
        SELECT stg_cd
        FROM tablea AS x
        WHERE x.CD = tablea.CD
    )
    AND srt_ordr > (
        SELECT srt_ordr
        FROM tableb
        WHERE stg_cd = 'CUSC'
    )
)

Demo on DB<>Fiddle

Answer 3

你可以喜欢

SELECT CD,
       stg_cd2
FROM
    T1 JOIN
    (
      SELECT TB1.stg_cd stg_cd1,
             TB1.srt_ordr srt_ordr1,
             TB2.stg_cd stg_cd2,
             TB2.srt_ordr srt_ordr2
      FROM T2 TB1 JOIN T2 TB2
      ON TB1.srt_ordr + 1 = TB2.srt_ordr
    ) TT
ON T1.stg_cd = TT.stg_cd1
WHERE T1.stg_cd = 'CUSC'

Demo

Answer 4

我会这样写：

SELECT * 
      FROM TABLEA AS A
     WHERE A.ID = 'APDN_82' 
       AND A.STG_CD IN (SELECT STG_CD 
                          FROM TABLEB 
                         WHERE SRT_ORDR IN (SELECT B.SRT_ORDR + 1 
                                              FROM TABLEB AS B 
                                             WHERE B.STG_CD = 'CUSC'
                                            )
                        )

使用表A中的当前数据选择表B中数据的下一个顺序

4 个答案: