Question

mylist = ['breast:entire breast quadrant ', 'breast:entire breast ', 'breast:entire breast and endocrine system ', 'breast:entire breast quadrant ', 'breast:entire breast ', 'breast:entire breast and endocrine system ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen and pelvis ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen ', 'chest:entire chest and abdomen and pelvis ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen ', 'chest:entire chest wall ', 'chest:entire chest wall artery ']

在上面的列表中，我有两个关键字（乳房和胸部）和相关值。我需要为每个关键字选择最小值（按字数）。

我希望选择1）'breast:entire breast ' 2）'chest:entire chest wall '

能请你帮忙吗？要在Python中执行。

Answer 1

您可以使用排序列表和字典来做到这一点。首先，您可以创建列表列表：

[x.split(':') for x in mylist]

结果是：

[['breast', 'entire breast quadrant '],
 ['breast', 'entire breast '],
 ['breast', 'entire breast and endocrine system '],
 ['breast', 'entire breast quadrant '],
 ['breast', 'entire breast '],
 ['breast', 'entire breast and endocrine system '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest and abdomen and pelvis '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest and abdomen '],
 ['chest', 'entire chest and abdomen and pelvis '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest and abdomen '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall artery ']

现在我们可以按第一个值和第二个值中单词的长度对其进行排序

sorted(
     [x.split(':') for x in mylist],
     key=lambda x: (x[0],len(x[1].split())),
     reverse=True
)

我们使用反向将min值放在排序列表的末尾，结果是：

[['chest', 'entire chest and abdomen and pelvis '],
 ['chest', 'entire chest and abdomen and pelvis '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest and abdomen '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest and abdomen '],
 ['chest', 'entire chest wall artery '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall '],
 ['chest', 'entire chest wall '],
 ['breast', 'entire breast and endocrine system '],
 ['breast', 'entire breast and endocrine system '],
 ['breast', 'entire breast quadrant '],
 ['breast', 'entire breast quadrant '],
 ['breast', 'entire breast '],
 ['breast', 'entire breast ']]

现在从排序列表中创建字典，该字典具有唯一键，因此在处理结果时，每个第一个值都将取最后一个值：

dict(sorted( 
    [x.split(':') for x in mylist], 
    key=lambda x: (x[0],len(x[1])), 
    reverse=True 
    ))

结果是

{'chest': 'entire chest wall ', 'breast': 'entire breast '}

Answer 2

mylist = ['breast:entire breast quadrant ', 'breast:entire breast ', 'breast:entire breast and endocrine system ', 'breast:entire breast quadrant ', 'breast:entire breast ', 'breast:entire breast and endocrine system ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen and pelvis ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen ', 'chest:entire chest and abdomen and pelvis ', 'chest:entire chest wall ', 'chest:entire chest wall artery ', 'chest:entire chest and abdomen ', 'chest:entire chest wall ', 'chest:entire chest wall artery ']

string1 = 'breast:'
string2 = 'chest:'
c1 = float("inf")
c2 = float("inf")
for x in mylist:
    if 'breast' in x :
        c_idx = x.index(':')
        x = x [ c_idx+1 : ]
        cnt = x.count(" ")
        if cnt < c1 :
            string_b = x
            c1 = cnt
        else :
            continue
    elif 'chest' in x :
        c_idx = x.index(':')
        x = x [ c_idx+1 : ]
        cnt = x.count(" ")
        if cnt < c2 :
            string_c = x
            c2 = cnt
        else :
            continue
print(string1+string_b)
print(string2+string_c)

希望这会有所帮助。

Answer 3

其他选项

sublisted = [ x.split(":") for x in set(mylist)]

breast = min([ item[1] for item in sublisted if item[0] == "breast" ], key=len)
chest = min([ item[1] for item in sublisted if item[0] == "chest" ], key=len)

print(breast) #=> entire breast 
print(chest) #=> entire chest wall

您可以自定义或构建一种方法来获取所需的字符串格式，例如：

sublisted = [ x.split(":") for x in set(mylist) ]

def find_min(lst, str):
  found = min([ item[1] for item in sublisted if item[0] == str ], key=len)
  return str + ': ' + found

keys = { x[0] for x in sublisted }
for k in keys:
  print(find_min(sublisted, k))
# chest: entire chest wall 
# breast: entire breast

从列表中选取最小的项目（字符串）

3 个答案: