Question

我正在使用MySQL Workbench 8.0。我正在尝试为正在运行的以下查询实现嵌套查询。我试图避免创建表命令。但是，它显示了错误。（Select在此服务器版本的此位置上无效，期望为'（'，带有）

可执行查询是

create table recent as
select f.member_id,f.fill_date,f.insurancepaid, 
p.member_first_name,p.member_last_name,d.drug_name,
row_number() over (partition by p.member_id order by f.fill_date desc) as flag
from fact_member_drug f 
left join dimension_drug_name p 
on f.member_id = p.member_id 
left join dim_drugdetail_table d 
on f.drug_ndc = d.drug_ndc;

select member_id,member_first_name,member_last_name,drug_name,fill_date,insurancepaid 
from recent where flag = 1;

我写的查询是

select sub.member_id,sub.member_first_name,sub.member_last_name,sub.drug_name,sub.fill_date,sub.insurancepaid 
from (
    select f.member_id,f.fill_date,f.insurancepaid, 
    p.member_first_name,p.member_last_name,d.drug_name,
    row_number() over (partition by p.member_id order by f.fill_date desc) as flag
    from fact_member_drug f 
    left join dimension_member p 
    on f.member_id = p.member_id 
    left join dimension_drug_name d 
    on f.drug_ndc = d.drug_ndc;
) as sub
where sub.flag = 1;

请帮助我做错什么。

谢谢

Answer 1

您可以尝试以下操作

   with cte as
   ( 
    select f.member_id,f.fill_date,f.insurancepaid, 
    p.member_first_name,p.member_last_name,d.drug_name,
    row_number() over (partition by p.member_id order by f.fill_date desc) as flag
    from fact_member_drug f 
    left join dimension_drug_name p 
    on f.member_id = p.member_id 
    left join dim_drugdetail_table d 
    on f.drug_ndc = d.drug_ndc
 )  select * from cte where flag=1

从查询中删除分号

select sub.member_id,sub.member_first_name,sub.member_last_name,sub.drug_name,sub.fill_date,sub.insurancepaid 
from (
    select f.member_id,f.fill_date,f.insurancepaid, 
    p.member_first_name,p.member_last_name,d.drug_name,
    row_number() over (partition by p.member_id order by f.fill_date desc) as flag
    from fact_member_drug f 
    left join dimension_member p 
    on f.member_id = p.member_id 
    left join dimension_drug_name d 
    on f.drug_ndc = d.drug_ndc // just remove semicolon
) as sub
where sub.flag = 1

尝试嵌套查询时，MYSQL Workbench错误

1 个答案: