这是我的api响应:
[
[
{
"id": 24,
"request_id": "rqst5c130cae6f7609.41056231",
"business_name": "Code Viable",
"business_email": "code@viable.com",
"title": "Load",
"details": "load",
"load_description": "load",
"amount_offered": "1",
"pickup_address": "load",
"dropoff_address": "load",
"timestamp": "2018-12-14 01:51:42"
}
],
[
{
"id": 27,
"request_id": "rqst5c1325881836d2.98441728",
"business_name": "Code Viable",
"business_email": "code@viable.com",
"title": "Load",
"details": "brendan",
"load_description": "test load for brendan",
"amount_offered": "1222",
"pickup_address": "Load",
"dropoff_address": "Load",
"timestamp": "2018-12-14 03:37:44"
}
]
]
如您所见,它是一个包装在数组内部的数组,我已经为内部数组设置了对象映射器,如下所示:
struct JobResponseDataObject: Mappable {
init?(map: Map) {
}
var id: Int?
var requestId: String?
var businessName: String?
var businessEmail: String?
var title: String?
var details: String?
var loadDescription: String?
var amountOffered: String?
var pickUpAddress: String?
var dropOffAddress: String?
var timestamp: String?
mutating func mapping(map: Map) {
id <- map["id"]
requestId <- map["request_id"]
businessName <- map["business_name"]
businessEmail <- map["business_email"]
title <- map["title"]
details <- map["details"]
loadDescription <- map["load_description"]
amountOffered <- map["amount_offered"]
pickUpAddress <- map["pickup_address"]
dropOffAddress <- map["dropoff_address"]
timestamp <- map["timestamp"]
}
}
如果父级为其子数组命名,那么我将为顶层创建另一个映射器。但是在这种情况下,外部数组没有名称,我该怎么做才能使alamofire .responseArray
调用正常工作?
Alamofire.request(JOB_REQUEST_BASE_URL, method: .post, parameters: parameter, encoding: URLEncoding(), headers: nil).responseArray { (response: DataResponse<[JobResponseDataObject]>) in
}
}
谢谢
答案 0 :(得分:0)
您的JSON对象具有嵌套的Array。因此,可以解析为两种方法。一种方法是将其解析为嵌套数组。
DataResponse<[[JobResponseDataObject]]>
您的代码将如下所示。
Alamofire.request(JOB_REQUEST_BASE_URL, method: .post, parameters: parameter, encoding: URLEncoding(), headers: nil).responseArray { (response: DataResponse<[JobResponseDataObject]>) in
//...
}
建议:到目前为止,我从JSON可以理解,它不应该位于嵌套数组中。如果只需要在嵌套数组中添加一个对象,则可以使用简单数组来实现相同的目的。
第二种方式 如果嵌套数组中只有一个对象。您还可以按以下方式对其进行解析。
requestId <- map["0.request_id"]
“ 0”。在这里获取内部数组的第一个对象。 希望这会有所帮助:)