将表格单元格值从javascript变量传递到php变量。
<script>
$(document).on('ready',function(){
$('#business_list_table').on('click','.view_btn',function (){
$.ajax({
url: "test.php",
method: "POST",
data:{business_id : "6510-1"},
success: function (data){
$('#business_permit_table').html(data);
}
});
});
});
<?php
$business_id = $_GET["business_id"];
echo $business_id;
答案 0 :(得分:2)
您不能像这样直接将JS变量直接用于PHP。改用ajax:
JS
$("#business_list_table").on('click', '.view_btn', function post() {
// get the current row
var currentRow = $(this).closest("tr");
var Business_id_value= currentRow.find("td:eq(1)").text(); // get current row 2nd T;
$.post('', {Business_ID: Business_id_value}, function(result){
$('table tbody').html(result);
});
});
PHP
if (isset($_POST['Business_ID'])) {
$Business_ID = $_POST['Business_ID'];
$conn = mysqli_connect("localhost", "root", "", "bpsystem");
if ($conn->connect_error) {
die("Database connection failed:" . $conn->connect_error);
} else {
$sql = "SELECT * FROM business_tb WHERE Business_ID='$Business_ID';";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
echo "<tr >";
echo "<td>BUSINESS NAME</td>";
echo "<td>" . $row['Business_Name'] . "</td>";
echo "</tr>";
echo "<tr >";
echo "</tr>";
}
}
}
}
答案 1 :(得分:0)
您可以使用查询字符串将变量传递给PHP。像这样
$("#business_list_table").on('click', '.view_btn', function post() {
// get the current row
var currentRow = $(this).closest("tr");
var Business_id_value= currentRow.find("td:eq(1)").text(); // get current row 2nd T;
window.location.href = 'http://your_url?b_id=' + Business_id_value;
});
现在,您可以使用$_GET['Business_id_value']