我有一个计数,在这里我检测到重复不止一次的元素。
select MstDocCabId, count (*) as 'Repetition Number'
from skmov (nolock)
group by MstDocCabId
having count(MstDocCabId) > 1
因此,结果类似于:
+-------------+-------------------+
| MstDocCabId | Repetition Number |
+-------------+-------------------+
| 16513519 | 4 |
+-------------+-------------------+
因此,如果我使用select * from skmov where MstDocCabId=16513519
,则可以看到4个具有相同mstdoccabid的元素,例如
+----------+----------+
| MstID | Col2 |
+----------+----------+
| 38600690 | 16513519 |
| 38600691 | 16513519 |
| 38600692 | 16513519 |
| 38600693 | 16513519 |
+----------+----------+
对于每一个重复 mstdoccabid 的行,都有一个名为 product 的列,对于每种情况,该列可能具有或应该具有不同的值:
+-----------+-------------+---------+
| MstID | mstdoccabid | Product |
+-----------+-------------+---------+
| 38600690 | 16513519 | AAAA |
| 38600691 | 16513519 | BBBB |
| 38600692 | 16513519 | CCCC |
| 38600693 | 16513519 | DDDD |
+-----------+-------------+---------+
我的问题是如何检测重复出现 mstdoccabid 且 product 相同的情况(例如产品AAAA)。
+-----------+-------------+---------+
| MstID | mstdoccabid | Product |
+-----------+-------------+---------+
| 38600690 | 16513519 | AAAA |
| 38600691 | 16513519 | BBBB |
| 38600692 | 16513519 | CCCC |
| 38600693 | 16513519 | AAAA |
+-----------+-------------+---------+
答案 0 :(得分:0)
也可以按Product
分组,它将起作用:
select MstDocCabId, count (*) as 'Repetition Number'
from skmov (nolock)
group by MstDocCabId, Product
having count(MstDocCabId) > 1