Question

我有一个对象数组，正在尝试使用过滤器和reduce来使输出正确显示。

它正在正确输出数据，但不是我想要的格式。任何输入都非常感谢。

当前输出

{
 5: 12,
 6: 15,
 7: 12,
 ...
}

预期输出

{
 session5-count: 12,
 session6-count: 15,
 session7-count: 12,
 ...
}

我确定这很简单，我还没有吃午饭，所以可能会阻碍我的思考过程。

这是我的公式和示例数据

更新功能

感谢 alex-g 和 zfrisch

const sessionsArray = [
    { session: '5', status: 'inactive' },
    { session: '5', status: 'inactive' },
    { session: '5', status: 'inactive' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '5', status: 'active' },
    { session: '6', status: 'active' },
    { session: '6', status: 'active' },
    { session: '7', status: 'inactive' },
    { session: '7', status: 'inactive' },
    { session: '7', status: 'inactive' },
    ];

const filteredSessions  = sessionsArray
    .reduce( (acc, {session, status}) => {

        if(status != 'active'){
           acc["session-" + session ] = 0
        }else{           
            acc["session-" + session ] =
            acc["session-" + session ] + 1 || 1
        } 
        
        return acc
    }, {}) 

console.log(filteredSessions )

我正在尝试并使用THIS S.O. ANSWER来帮助格式化输出

Answer 1

您可以使用模板字符串来获取所需的密钥格式。像这样：

const sessionsArray = [
{ session: '5', status: 'inactive' },
{ session: '5', status: 'inactive' },
{ session: '5', status: 'inactive' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '5', status: 'active' },
{ session: '6', status: 'active' },
{ session: '6', status: 'active' },
{ session: '7', status: 'inactive' },
{ session: '7', status: 'active' },
{ session: '7', status: 'active' },
];

const filteredSessions = sessionsArray
    .filter(workshop => workshop.status === 'active')
    .reduce( (acc, { session }) => {
        
        acc[`session${session}-count`] = acc[`session${session}-count`] + 1 || 1;
        
        return acc;
    }, {});

console.log(filteredSessions)

格式化对象输出数组

1 个答案: