如果列表中不存在键，则从列表字典中删除字典

Question

abc = [123,345,678]
var = [{'name':'123, 'age':12},{name:345, 'age':32},{name:789,'age':39}]

如果var ['name']在列表abc中不存在，我想从var中删除字典。

final = [{'name':'123, 'age':12},{name:345, 'age':32}]

我尝试了以下

for i,element in enumerate(abc):
   if element['name'] in var.keys():
      element['salary'] = '50000'
   else:
       abc.pop(i)

它删除了一些字典，但留下了一个字典

Answer 1

这是一个列表理解方法：

final = [v for v in var if v['name'] in abc]

Answer 2

final = filter(lambda x: x['name'] in abc, var)

Answer 3

推荐使用集合参考Complexity of *in* operator in Python

set_abc = set(abc)
final = [x for x in var if x['name'] in set_abc]