我在SQL Server中有一个表:产品
产品表:
ImageID ProductID
------- ----------
1 P1
1 P2
1 P3
2 S1
2 S2
2 S3
3 M1
这是我需要的输出:
ImageID Product1ID Product2ID Product3ID
----------- ---------- ---------- ----------
1 P1 P2 P3
2 S1 S2 S3
3 M1 null null
一个ImageID最多可以有3个ProductID 并非所有ImageID都有3种产品[例如, ImageID = 3]
SELECT ImageID, [Product1ID], [Product2ID], [Product3ID]
FROM
(
SELECT ImageID, ProductID
FROM ProductTable
) AS P
PIVOT
(
max( ImageID)
FOR ProductID IN ([Product1ID], [Product2ID], [Product3ID])
) AS PVT
答案 0 :(得分:4)
我只会使用条件聚合:
SELECT ImageID,
MAX(CASE WHEN seqnum = 1 THEN ProductID END) as Product1ID,
MAX(CASE WHEN seqnum = 2 THEN ProductID END) as Product2ID,
MAX(CASE WHEN seqnum = 3 THEN ProductID END) as Product3ID
FROM (SELET pt.*, ROW_NUMBER() OVER (PARTITION BY ImageId ORDER BY ProductID) as seqnum
FROM ProductTable
) P
GROUP BY ImageID;
但是,关键思想是使用ROW_NUMBER()
来枚举产品。
答案 1 :(得分:3)
您非常接近,您只需要合并Row_Number()
示例
Select *
From (
Select ImageID
,Item = concat('Product',row_number() over (partition by ImageID order by ProductID),'ID')
,ProductID
From ProductTable
) src
Pivot (max(ProductID) for Item in ([Product1ID], [Product2ID], [Product3ID])) pvt