Question

感谢大家在这里的帮助。我已经解决了我的代码问题。

Answer 1

除了使用while True之外，您还可以使用以下内容：

gamecount = 0
while (gamecount < 5):
   print (f'play game {gamecount}') 
   #insert your other game code here
   gamecount += 1

还要记住，按照@Eliad Cohen在回答中所说的，删除代码中的break。

Answer 2

乍一看，除非您将导入移动到第一行并缩进“ for”循环下的所有内容，否则此代码块将不会运行。您的代码现在正在执行的操作只是将随机模块导入五次。另外，在第11行中使用之前，必须实例化scoreOne。我同意@ycx注释，我认为使用while循环会更好。我认为您在第57行中使用break会使循环在您希望结束之前结束。您可以在http://www.tutorialspoint.com/python/python_loop_control.htm

中阅读有关循环控制的更多信息。

希望到目前为止有帮助。

Answer 3

正如其他答案所指出的那样，代码的缩进和排序已关闭。这可能是编程错误，也可能是将代码复制到堆栈溢出的结果。

除了缩进，脚本还有很多重复的代码。为了减少代码重复并使脚本更易于阅读和理解，您可能希望将程序分成不同的functions。

尽管我不打算废除您以前的作品，但这是我对游戏的实现（据我所了解），因此您可以了解一个人如何构建一个简单的脚本。我的确意识到有更优雅的方式来实现游戏，但是为了清楚起见，我决定坚持使用通用的代码构造。

#! /usr/bin/env python3
# imports
from random import randint


# functions
def roll_dice(n_dice):
    """Rolls specified number of dice and returns their values"""
    # wait until the player types 'roll'
    while True:
        answer = input("Type 'roll' to roll the dice: ")
        if answer.lower() == "roll":
            break
    # generate results using list comprehension
    results = [randint(1, 6) for die in range(n_dice)]
    print("you rolled: ", results)
    return results


def play_turn(player_name):
    """Lets specified player play a turn and returns the resulting score"""
    print(player_name, " it's your turn to play!")
    # roll two dice
    roll_one, roll_two = roll_dice(2)
    print(type(roll_one))
    score = roll_one + roll_two

    # if it was a double, roll die no 1 again
    if roll_one == roll_two:
        print("You rolled a double!", "Roll again", sep="\n")
        roll_one = roll_dice(1)[0]
        score += roll_one

    if roll_one % 2 == 0 or roll_two % 2 == 0:  # if at least one die has an even value:
        score += 10
    else:
        score -= 5
    print("you scored", score, "points", "\n")
    return score


def play_game(player_names):
    """runs the game, given a collection of player names"""
    # set up a score board.
    # # This can be implemented more elegantly, but this solution is most clear, I think.
    # the alternative would be a dictionary comprehension: score_board = {player: 0 for player in player_names}
    score_board = dict()
    for player in player_names:
        score_board[player] = 0

    # do 5 rounds of regular playing, adding extra rounds if the game ties
    round_no = 0
    while True:
        for player in player_names:
            score = play_turn(player)
            score_board[player] = max(0, score_board[player] + score)  # make sure the score doesn't drop below 0
        print("current scores are", score_board)
        round_no += 1
        # after 5 normal rounds have been played:
        if round_no >= 5:
            if len(set(score_board.values())) == 1:  # if the game tied:
                print("game tied. Let's play until someone wins!")
                continue
            else:
                # determine who won
                max_score = max(score_board.values())
                for player in score_board:
                    if score_board[player] == max_score:
                        print(player, "won with a score of", max_score)
                return  # a return will exit the function and thus break the loop


def main():
    """The main function controls the entire program on a high level"""
    player_names = ("player 1", "player 2")
    play_game(player_names)
    return


# These lines make sure the game won't start when this file is imported using 'import'
if __name__ == '__main__':
    main()

两人骰子游戏与排行榜

3 个答案: