Question

我对CodeIgniter和我想将我的网址更改为

到

在带有路由的CI中。如何使用URL Route实现此目的？

我的餐桌发帖

posts_id
posts_name

我的主视图（以拨打电话）

我使用网址标题作为网址：

<a href="<?php echo base_url("{$v['posts_id']}/".url_title($v['posts_name'], "-", true)) ?>">

我的帖子控制器

    <?php 
defined('BASEPATH') OR exit ('No direct script access allowed');
class Posts extends CI_Controller {
    public function __construct()
    {
        parent::__construct();
        $this->load->model('Posts_model');
    }
    public function index()
    {
        show_404();
    }
    public function details($posts_id=NULL,$posts_name='') {
        $data['title'] = $this->Posts_model->select_content_by_id($posts_id);
        $data['data'] = $this->Posts_model->select_content_by_id($posts_id);
        $this->load->view('posts',$data);
    }
}

我的帖子模型

 <?php 
defined('BASEPATH') OR exit ('No direct script access allowed');
class Posts_model extends CI_Model{
    public function dsPosts()
    {
        return $this->db->get('posts')->result_array();
    }
    public function select_content_by_id($posts_id)
    {
        return $this->db->where('posts_id',$posts_id)->get('posts')->result_array();
    }
}

我的路线

$route['default_controller'] = 'home';
$route['404_override'] = '';
$route['(:num)'] = 'posts/details/$1';
$route['(:num)/(:any)'] = 'posts/details/$1/$2';

Answer 1

您已经接近答案

$route['(:any)-(:num)'] = 'posts/details/$2/$1';

然后查看

<a href="<?php echo base_url(url_title($v['posts_name'], "-", true)."-{$v['posts_id']}".) ?>">

仅此而已。但我建议您将网址写得更清楚，因为您可以拥有多个控制器！如果您有 comments 控制器并想从中获取数据，该怎么办？ （：any）表示可以是任何

具有ID和标题的CodeIgniter URL路由

1 个答案: