Question

如何仅使用20或50年代的纸币从ATM机中提取适当的金额？例如，如果我要提取130欧元，则机器应给我1张50的钞票和4张20的钞票。

要使其正常工作真的很困难。有人可以帮我吗？

我只能这样做：

#include <stdio.h>

int main() {
  int balance = 500;
  int withdraw;
  int bill_20, bill_50;

  printf("How much you want to withdraw?");
  scanf("%d", &withdraw);

  if ((withdraw >= 20) && (withdraw <= balance) && (withdraw % 10 == 0)
      && (withdraw != 30)) {

    if (withdraw >= 50) {
      bill_50 = withdraw / 50;
      withdraw = withdraw % 50;
      printf("You get %d bills of 50s\n", bill_50);
    }
    if ((withdraw >= 20) && (withdraw < 50)) {
      bill_20 = withdraw / 20;
      withdraw = withdraw % 20;
      printf("You get %d bills of 20s\n", bill_20);
    }

  } else
    printf("Wrong sum");

  return 0;
}

Answer 1

好吧，分步进行：

最大容纳50秒。
如果其余的不能在20秒钟之内拿走，而我们至少拿了一个50，则再把一个50放回去。
采取其他适合的20s。
如果还有什么，请绝望。

int bill_50 = withdraw / 50 - (withdraw > 50 && withdraw % 50 % 20);
int bill_20 = (withdraw - bill_50 * 50) / 20;
if (withdraw != bill_50 * 50 + bill_20 * 20)
    printf("Cannot put it together.\n");

Answer 2

您可以尝试每次从 withdraw 中减去该值。我这样修改了您的代码。希望这会有所帮助。

  #include 

int main（）{

    整型余额= 500;
    撤回;
    二十多岁= 0;
    五十年代= 0;

    printf（“您要提取多少？\ n”）;

    scanf（“％d”，＆withdraw）;

    如果（提取>余额）{

        printf（“您没有这种钱。\ n”）;

        返回0;
    }

    否则，如果（提现<= 30 ||提现％10！= 0）{

        printf（“您只能提取20s和50s。\ n”）；

        返回0;
    }

    同时（提款> 50）{

        二十多岁++;

        提现-= 20;
    }

    如果（提现== 50）五十多岁++;

    否则二十多岁== 2;

    printf（“您有％d 20s和％d 50s \ n”，二十，五十年代）；
}

ATM仅使用50和20的纸币进行取款C

2 个答案: